Derivative of a right circular cone

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SUMMARY

The discussion focuses on calculating the rate of change of depth in an inverted right circular cone with a top radius of 15 meters and a depth of 12 meters, given a volume flow rate of 2 cubic meters per minute. The relationship between the radius (r) and depth (h) is established through the geometry of the cone, leading to a differential equation that expresses dV/dt in terms of dh/dt. At a depth of 8 meters, the specific rate of increase in depth is sought, requiring the application of related rates in calculus.

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b.mueller5
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inverted right-circular cone, with radius at the top 15 meters and depth 12 meters. rate of 2 cublic meters per minute. How fast is the depth increasing at the instant when the depth is 8 meters.

When i try to solve it I get an equation with 2 varibles.
 
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Note that one can relate radius r at any point to the depth h at that point. Then dV/dt will be in terms of dh/dt only.
 
Think of one side of the cone as starting at (0, 0) and going to (15, 12). What is the equation of that line?
 

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