Derivative of Complex Variables

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Discussion Overview

The discussion centers around the differentiation of a complex variable expression, specifically the derivative of the squared modulus of a complex expression with respect to a complex variable. Participants explore the implications of complex differentiation and the use of different derivative definitions.

Discussion Character

  • Technical explanation
  • Debate/contested
  • Mathematical reasoning

Main Points Raised

  • One participant asks for the derivative of |b-ax|^2 with respect to x*, suggesting it may involve Wirtinger derivatives.
  • Another participant questions the clarity of the derivative's meaning and proposes that the derivative could be -a(b-ax)*.
  • There is a suggestion that the derivative might also be expressed as -(b-ax)a*; however, the participant is unable to prove this claim.
  • Some participants note that |b-ax|^2 is not complex differentiable since it depends on both x and x*.
  • A later reply discusses the various ways a complex variable can be represented, indicating that different coordinate systems can be used to compute the derivative.
  • One participant mentions that the chain rule can be applied with different variables to find the partial derivative with respect to x.

Areas of Agreement / Disagreement

Participants express differing views on the meaning and implications of the derivative in question. There is no consensus on the correct form of the derivative or its interpretation, indicating ongoing debate.

Contextual Notes

Participants highlight the complexity of differentiating functions of complex variables, noting the dependence on both x and x*, which complicates the notion of complex differentiability.

EngWiPy
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Hi,

What is the following derivative:

[tex]\frac{\partial}{\partial x}|b-ax|^2[/tex]?

Now I know that [tex]|b-ax|^2=(b-ax)(b^*-a^*x^*)[/tex], so how to do the differentiation with respect to [tex]x^*[/tex]?

Thanks in advance

PS.: All variables and constants are complex.
 
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Is this a homework question?
 
It is not clear what that derivative means.
A guess would be that it is a Wirtinger derivative in which case we have
[tex]\frac{\partial x^*}{\partial x}=0[/tex]
 
Mark44 said:
Is this a homework question?

No it is not.

So lurflurf, are you saying that the derivative will be:

[tex]-a(b-ax)^*[/tex]

I thought it will be like:

[tex]-(b-ax)a^*[/tex]

but I couldn't prove it.
 
Again it is not clear what that derivative means, but a good guess would be -a(b-ax)*.
Then we have
d|b-a x|^2=-a(b-a x)* dx+-a*(b-a x) dx*

notice that |b-a x|^2 is definitely not complex differentiable as it depends upon x and x* rather than upon x alone
 
lurflurf said:
Again it is not clear what that derivative means, but a good guess would be -a(b-ax)*.
Then we have
d|b-a x|^2=-a(b-a x)* dx+-a*(b-a x) dx*

notice that |b-a x|^2 is definitely not complex differentiable as it depends upon x and x* rather than upon x alone

No, I just need to the derivative [tex]\frac{\partial}{\partial x}[/tex], where the derivative is partial with respect to x. I see some books writing x as a+jb, and then compute the derivatives with respect to a and b. I was just wondering if there is another way to do this.

Thanks
 
There are different ways because a complex variable can change in more ways than a real variable. We can work with different coordinates or none. So a function of a complex variable can be described in diferent ways with two variables
|x| and arg(x)
Re(x) and Im(x)
x and x*
and so on

since you are interested in the x partial x and x* are natural, but you could use any set and the chain rule to find the x partial.
[tex]\frac{\partial}{\partial x}=\frac{\partial u}{\partial x}\frac{\partial}{\partial u}+\frac{\partial v}{\partial x}\frac{\partial}{\partial v}[/tex]
However you want to choose u and v
 

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