Derivative of e^x Power Series: Own Power Series

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SUMMARY

The discussion focuses on differentiating the power series representation of the exponential function, specifically demonstrating that the derivative of the series \(\sum_{n=0}^{\infty }\frac{x^{n}}{n!}\) equals the original series. Participants clarify that the differentiation is performed with respect to \(x\) and that \(n!\) acts as a constant during differentiation. Key insights include the application of the sum rule of differentiation, allowing the interchange of differentiation and summation, which simplifies the process of finding the derivative of the series.

PREREQUISITES
  • Understanding of power series and their convergence
  • Familiarity with basic calculus concepts, including differentiation
  • Knowledge of the factorial function and its properties
  • Ability to apply the sum rule of differentiation
NEXT STEPS
  • Study the properties of power series and their derivatives
  • Learn about the sum rule of differentiation in detail
  • Explore examples of differentiating series term-by-term
  • Investigate the relationship between power series and exponential functions
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Students and educators in calculus, mathematicians interested in series analysis, and anyone looking to deepen their understanding of differentiation techniques in power series.

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Homework Statement


I need to demonstrate that \frac{\mathrm{d} }{\mathrm{d} x}\sum_{n=0}^{\infty }\frac{x^{n}}{n!}= \sum_{n=0}^{\infty }\frac{x^{n}}{n!}

Homework Equations

The Attempt at a Solution



I just need a hint on how to start this problem, so how would you guys start this problem?
 
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Carry out the differentiation explicitly.
 


Thanks for the quick reply, but I don't see how to take the derivative of the n factorial. could you please provide me with an example of how to do it?.Thanks
 


The n factorial is just a constant. The differentiation is with respect to x.
 


Okay I just got a weird answer, which I think its wrong. \frac{\mathrm{d} }{\mathrm{d} x}=\frac{(n!)}{nx^{n-1}} could you give some steps cause for me its weird to differentiate explicitly with n and factorial.
 


Do you know how to differentiate x^n with n a constant? If so do you know how to differentiate constant*x^n? What if the constant equals 1/n!?
 


okay. if the result its 1/n! how is that related to the power series?
 


The result isn't 1/n!. I asked you three questions in post #6 and you avoided answering all three. If you want help you will need to cooperate.
 


Oh sorry. The only thing I can say is this dx/dx= n(x^n-1)(1)/n!
 
  • #10


That is correct. Furthermore from the sum rule of differentiation you know that (f(x)+g(x))'=f'(x)+g'(x). Therefore you can just interchange differentiation and summation. If you don't see it just write out the first few terms.
 
  • #11


Honestly, I don't see it. what should I consider f(x) and g(x) ? because I only see n(x^n-1)(1)/n! as f(x).Sorry if I cause you trouble..
 
  • #12


f and g are just two functions. You are dealing with a sum of more than two functions. Nevertheless the sum rule still applies in the same way and you can interchange differentiation and summation.
 

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