Derivatives of implicit realtionships.

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SUMMARY

The discussion focuses on the implicit differentiation of the equation $y^3 + 5x^2 = 5x - 2y$. Participants confirm that it is indeed possible to differentiate this equation using the chain rule. The process involves differentiating both sides with respect to $x$, leading to the equation $3y^2\frac{dy}{dx} + 10x = 5 - 2\frac{dy}{dx}$. The final expression for $\frac{dy}{dx}$ can be derived by solving this equation, demonstrating the application of implicit differentiation techniques.

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  • Familiarity with the chain rule in calculus
  • Basic knowledge of derivatives and their notation
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  • Practice implicit differentiation with various equations
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Petrus
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Hello,
Today did me and my friend talked of derivate and he asked about some help. Then he asked me is it possible to derivate $y^3+5x^2=5x-2y$ and i was clueless how i derivate that. Is this difficoult to derivate?is it possible to do it?
 
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Re: Derivate of functions.

Petrus said:
Hello,
Today did me and my friend talked of derivate and he asked about some help. Then he asked me is it possible to derivate $y^3+5x^2=5x-2y$ and i was clueless how i derivate that. Is this difficoult to derivate?is it possible to do it?
You need to use the chain rule. This says that if $z$ is a function of $y$ and $y$ is a function of $x$ then $\dfrac{dz}{dx} = \dfrac{dz}{dy}\dfrac{dy}{dx}.$ So for example if you want to differentiate $y^3$ with respect to $x$, the chain rule says that $\dfrac{d}{dx}(y^3) = 3y^2\dfrac{dy}{dx}.$ You can then differentiate both sides of the equation $y^3+5x^2=5x-2y$ with respect to $x$, to get $3y^2\frac{dy}{dx}+ 10x = 5 -2\frac{dy}{dx}.$ Now solve that equation to find an expression for $\frac{dy}{dx}.$

That process is called implicit differentiation.
 
Re: Derivate of functions.

Petrus said:
Hello,
Today did me and my friend talked of derivate and he asked about some help. Then he asked me is it possible to derivate $y^3+5x^2=5x-2y$ and i was clueless how i derivate that. Is this difficoult to derivate?is it possible to do it?

If You write the equation as...

$\displaystyle f(x,y)= y^{3} + 2\ y + 5\ x^{2} - 5\ x =0$ (1)

... You obtain the implicit definition of a function $y= \varphi(x)$. In the XVIII century the Italian mathematician and senator of the Kingdom Ulisse Dini demonstrated that, under appropriate conditions, the derivative of that function can be obtained as... $\displaystyle \varphi^{\ '}(x)= - \frac{f^{\ '}_{x}(x,y)}{f^{\ '}_{y}(x,y)}$ (2)Kind regards $\chi$ $\sigma$
 

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