Derive expression for induced voltage and current

In summary, this conversation discusses a question about a circular conducting loop with a slow sinusoidal voltage applied to it. The conversation includes equations for the potential difference induced in the inner loop and the current through that loop. The final answer for the potential difference includes a cosine term and the magnetic field is calculated using the loop's resistance and the constant μ0.
  • #1
hopkinmn
23
0

Homework Statement



A circular conducting loop with radius a and resistance R2 is concentric with a circular conducting loop with radius b much greater than a and resistance R1. A Resistance dependent voltage is applied to the larger loop, having a slow sinusoidal variation in time given by V(t) = V0 sin ωt, where V0 and ω are constants with dimensions of voltage and inverse time, respectively. Assuming that the magnetic field throughout the inner loop is uniform (constant in space) and equal to the field at the center of the loop, derive expressions for the potential difference induced in the inner loop and the current i through that loop.

Homework Equations



Vind=(d/dt)AB
where A is the area: A=∏a^2
and B is magnetic field

I1=V0/R1
I2=-Vind/R2

The Attempt at a Solution



My understanding is that d/dt=ωcos(ωt)
and B=μ0*I1/(2*∏*b)=μ0*V0/(2*b*∏*R1)

The answer for Vind=-∏*a^2*μ0*V0*ω*cos(ωt)/(2*b*R1)
What I don't understand is what happened to ∏ in B=μ0*V0/(2*b*R1)?
 

Attachments

  • Screen Shot 2012-03-13 at 3.51.37 PM.png
    Screen Shot 2012-03-13 at 3.51.37 PM.png
    6.3 KB · Views: 473
Physics news on Phys.org
  • #2
hopkinmn said:
My understanding is that d/dt=ωcos(ωt)
and
B=μ0*I1/(2*∏*b)=μ0*V0/(2*b*∏*R1)
The answer for Vind=-∏*a^2*μ0*V0*ω*cos(ωt)/(2*b*R1)
What I don't understand is what happened to ∏ in B=μ0*V0/(2*b*R1)?

Check the formula. There should be no pi in the denominator.

http://hyperphysics.phy-astr.gsu.edu/hbase/magnetic/curloo.html

ehild
 

FAQ: Derive expression for induced voltage and current

1. What is induced voltage and current?

Induced voltage and current are phenomena that occur when there is a change in magnetic flux through a conductor, which then produces an electric field and induces a current. This is known as electromagnetic induction.

2. How do you derive the expression for induced voltage and current?

The expression for induced voltage and current can be derived using Faraday's Law of Induction, which states that the induced voltage is equal to the rate of change of magnetic flux through a conductor. This can be represented as V = -N(dΦ/dt), where V is the induced voltage, N is the number of turns in the conductor, and dΦ/dt is the rate of change of magnetic flux.

3. What factors affect the magnitude of induced voltage and current?

The magnitude of induced voltage and current depends on the strength of the magnetic field, the speed at which the magnetic field changes, the number of turns in the conductor, and the angle between the conductor and the magnetic field. Additionally, the material of the conductor and its resistance can also affect the magnitude of the induced current.

4. Can induced voltage and current be used in practical applications?

Yes, induced voltage and current have many practical applications, such as in generators, transformers, and electric motors. They are also used in devices like induction cooktops and wireless chargers.

5. What is the difference between induced voltage and current and externally applied voltage and current?

Induced voltage and current are produced by a changing magnetic field, while externally applied voltage and current are produced by an external power source. Induced voltage and current are also dependent on the magnitude and direction of the magnetic field, while externally applied voltage and current can be controlled by the user. Additionally, induced voltage and current are often AC, while externally applied voltage and current can be either AC or DC.

Back
Top