Derived values not satisfying equations.

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Homework Help Overview

The discussion revolves around the conservation of kinetic energy and momentum in a scenario involving two colliding bodies moving in the same direction, with one body significantly faster than the other. The original poster derived values for the final velocities based on these principles but found discrepancies in the results.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to derive final velocities using conservation equations but encounters inconsistencies. Some participants suggest checking the quadratic equation solutions and performing sanity checks against expected physical behavior, such as one of the roots equating to the initial velocity of the faster body.

Discussion Status

Participants are actively engaging with the problem, pointing out potential errors and suggesting checks. The original poster acknowledges corrections but continues to experience issues, indicating an ongoing exploration of the problem without a clear resolution yet.

Contextual Notes

There are indications of careless errors in calculations, and the discussion reflects a focus on verifying assumptions and ensuring the derived values comply with the laws of physics. The original poster's attempts to reconcile the equations suggest a complex interaction of variables that may not be fully resolved.

dE_logics
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I derived some values from 2 equations...the values are such that its not complying with one of the equations -

Considering scenario of 2 colliding bodies, in this case both move in the same direction but one is much faster.
u1 = 80
u2 = 500
v1 = ?
v2 = ?
m1 = 100
m2 = 10

Forming equation for law of conservation of K.E -

m1*u1^2 + m2*u2^2 = m1*v1^2 + m2*v2^2

100*6400 + 10*250000 = 100*v1^2 + 10*v2^2

640000 + 2500000 = 100*v1^2 + 10*v2^2

314000 = 10*v1^2 + v2^2...1

Forming equation for law of conservation of Momentum -
m1*u1 + m2*u2 = m1*v1 + m2*v2

8000 + 5000 = 100v1 + 10v2

13000 = 100v1 + 10v2

13000 = 100v1 + 10v2

1300 = 10v1 + v2...2

130 - v2/10 = v1

Substitute v1 in 1 -

314000 = 10*(130 - v2/10)^2 + v2^2

314000 = 10*(16900 + (v2^2)/100 - 26v2) + v2^2

31400 = 16900 + (v2^2)/100 - 26v2 + v2^2

31400 = 16900 - 26v2 + 1.01v2^2

0 = -14500 - 26v2 + 1.01v2^2

0 = 14500 + 26v2 – 1.01v2^2

By quadratic equation formula -

v2 = 107.6364125 and -133.3789860

The negative value will be correct since the body will recoil.
Taking negative value and substituting it in equation 2-

1300 = 10v1 - 133.3789860

v1 = 143.3378986

Values do not comply with conservation of K.E

Taking positive value -

1300 = 10v1 – 107.6364125

v1 = 140.7636412

Error was pointed out by jtbell...and is now fixed.
 
Last edited:
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dE_logics said:
314000 = 10*v1^2 + v2^2...1

130 - v2/10 = v1

Substitute v1 in 1 -

314000 = 10*(130 - v2/10) + v2^2

Do you see your error now?
 
Thanks for that man...I edited that question...and the problem still persists after correction.
 
I haven't got time to go back over the details right now, but I can suggest a "sanity check." When you solve the quadratic equation to get v2, one of the roots should equal the original u2. This corresponds to the two objects "passing through each other" without interacting, in which case the total momentum and total KE are obviously conserved.
 
I think something's wrong with the quadratic equation...the sanity check has failed.

But I don't know what's wrong.
 
Problem solved...one of my many careless errors.

Considering scenario of 2 colliding bodies, in this case both move in the same direction but one is much faster.
u1 = 80
u2 = 500
v1 = ?
v2 = ?
m1 = 100
m2 = 10

Forming equation for law of conservation of K.E -

m1*u1^2 + m2*u2^2 = m1*v1^2 + m2*v2^2

100*6400 + 10*250000 = 100*v1^2 + 10*v2^2

640000 + 2500000 = 100*v1^2 + 10*v2^2

314000 = 10*v1^2 + v2^2...1

Forming equation for law of conservation of Momentum -
m1*u1 + m2*u2 = m1*v1 + m2*v2

8000 + 5000 = 100v1 + 10v2

13000 = 100v1 + 10v2

1300 = 10v1 + v2...2

130 - v2/10 = v1

Substitute v1 in 1 -

314000 = 10*(130 - v2/10)^2 + v2^2

314000 = 10*(16900 + (v2^2)/100 - 26v2) + v2^2

314000 = 169000 + (v2^2)/10 – 260v2 + v2^2

314000 = 169000 – 260v2 + 1.1v2^2

0 = -145000 – 260v2 + 1.1v2^2

0 = +145000 + 260v2 – 1.1v2^2

v2 = 500
v2 = -263.63636363 or -2900/11
alternative -

v1 by eq. 2 = 156.3636363636363636 or 1720/11

Equations satisfied.
 

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