Deriving acceleration r'' from velocity r' using chain rule

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yugeci
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Homework Statement



Worked derivation of velocity and acceleration using the chain rule: r-dot = 100(sec θ tan θ)θ-dot, and r-double-dot expanded into terms with sec θ tan θ, sec² θ and θ-double-dot.


How does one get the r" equation from r'?

Homework Equations



r = distance
v = r' = ds/dt
a = r'' = dv/dt

chain rule, dy/dt = dy/dx * dx/dt

The Attempt at a Solution



I can easily get to r' from r using the chain rule but how do you derive r" from r'? How do you apply the chain rule when there are 3 variables (sec theta, tan theta and theta dot)?

Help would be appreciated.
 
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[itex]\frac{d}{dt} f(a(t),b(t),c(t))=\frac{\partial f}{\partial a}\dot a+\frac{\partial f}{\partial b} \dot b+\frac{\partial f}{\partial c} \dot c[/itex]
 
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