1. Not finding help here? Sign up for a free 30min tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Fundamental Theorem of Calc Problem using Chain Rule

  1. Sep 9, 2016 #1
    1. The problem statement, all variables and given/known data
    F(x) = (integral from 1 to x^3) (t^2 - 10)/(t + 1) dt
    Evaluate F'(x)

    2. Relevant equations
    Using the chain rule

    3. The attempt at a solution
    Let u = x^3
    Then:
    [((x^3)^2 - 10) / (x^3 + 1)] ⋅ 3x^2
    *step cancelling powers of x from fraction*
    = (x^3 - 10)(3x^2)
    = 3x^5 - 30x^2

    I am trying to input a solution to a Maple TA problem for uni work, is this answer incorrect, or is possible that my maple TA syntax is incorrect.
    My attempted answer on maple looked like:
    (3*x^5) - (30*x^2)

    Any help that *doesn't* just give me the answer is very much appreciated!
     
  2. jcsd
  3. Sep 9, 2016 #2

    ShayanJ

    User Avatar
    Gold Member

    This is correct. But what happened to the denominator after this?
     
    Last edited: Sep 9, 2016
  4. Sep 9, 2016 #3
    In the cancelling step:
    [(3x^6 - 10)/(x^3 + 1)] ⋅ 3x^2
    It cancelled to give:
    (x^3 - 10) ⋅ 3x^2
     
  5. Sep 9, 2016 #4

    ShayanJ

    User Avatar
    Gold Member

    You can't do that!
    I don't even see how you're making that mistake to explain why its wrong!
     
  6. Sep 9, 2016 #5
    :/ Okay, my bad.

    Retry:
    [(x^6 - 10)/(x^3 + 1)] ⋅ 3x^2
    = (3x^8 - 30x^2)/(x^3 + 1)
     
  7. Sep 9, 2016 #6
    Aha! And entering that into Maple TA works!
    Thanks for your help!
     
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook

Have something to add?
Draft saved Draft deleted



Similar Discussions: Fundamental Theorem of Calc Problem using Chain Rule
Loading...