Deriving e^(-iAx) = cos(x)I + isin(x)A for Pauli matrices

  • Level: Graduate 
  • Thread starter Thread starter ArjSiv
  • Start date Start date
  • Tags Tags
    Pauli Rotations
Join the discussion
Registration is free. Start your own thread to ask a follow-up.
2 replies · 2K views
ArjSiv
Messages
5
Reaction score
0
So it's apparently possible to prove that e^{-iAx} = cos(x)I + isin(x)A given that A^2=I.

What I don't understand is how this is supposed to be derived. Any help would be appreciated as this is driving me nuts and this is probably something that is very easy to prove...
 
Physics news on Phys.org
Ahh, I knew I was missing something stupid. I didn't realize that A^{2n}A = A.

Thanks :)