Deriving Formula for Radius of Conical Section at Height h

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Homework Help Overview

The discussion revolves around deriving the formula for the radius of a conical section, specifically a frustum of a cone, at a certain height 'h' below the total height 'l'. The original poster presents a problem involving a right circular cone with two radii 'a' and 'b', where 'a' is greater than 'b'.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants suggest using similar triangles to derive the radius at height 'h'. There is discussion about the correct terminology, with some clarifying that the shape in question is a frustum of a cone. Others express skepticism about the applicability of similar triangles for this problem.

Discussion Status

Participants are actively engaging with the problem, offering various geometric interpretations and methods. Some guidance has been provided regarding the use of similar triangles, and there is a collaborative atmosphere as participants share insights and clarify terminology. However, there is no explicit consensus on the best approach yet.

Contextual Notes

There is some confusion regarding the terminology used to describe the conical section, with participants discussing the implications of referring to it as a "frustrated cone" versus a "frustum of a cone." Additionally, the original poster's constraints regarding the height 'h' being less than 'l' are noted.

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Homework Statement



Suppose there is a Conical section (of a right circular cone) of total height 'l' and radii 'a' and 'b' (a>b). How do we derive the formula for the radius at a height 'h' (h<l) ?

Homework Equations


The Attempt at a Solution

 
Last edited:
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Draw a cross section through the middle and look for similar triangles whose properties you can use to solve your problem. (I think you are describing a frustrated cone, not a pure cone?)
 
I am talking about this (see attached file).
 

Attachments

  • cone.jpg
    cone.jpg
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pongo38 said:
Draw a cross section through the middle and look for similar triangles whose properties you can use to solve your problem. (I think you are describing a frustrated cone, not a pure cone?)
Good advice, but the term is "frustum of a cone."
 
Mark44 said:
Good advice, but the term is "frustum of a cone."

Haha :smile: (or in other words, a truncated cone)
How was his advice good? We can't use similar triangle property to find the radius.
 
Extend the vertical line at the center and the outer sloped line up until they meet, then you'll have similar triangles.
 
Forget the 3 dimensional aspect; it would be easier to think of a trapezoid with one side of length l[/tex], perpendicular to sides a &amp; b. Call the remaining side c.<br /> <br /> a &amp; b still represent the upper and lower radii of your truncated cone, and r represents the radius of that object at height <i>h</i> above side a.
 

Attachments

  • Trapezoid4.png
    Trapezoid4.png
    1.3 KB · Views: 460
Mark44 said:
Extend the vertical line at the center and the outer sloped line up until they meet, then you'll have similar triangles.

I find the algebra easier if you construct the additional 2 line segments shown in the attached drawing.
 

Attachments

  • Trapezoid5.png
    Trapezoid5.png
    1.3 KB · Views: 481
Thanks a lot zgozvrm. I got my answer :smile:
 
  • #10
Glad to help.

What did you come up with?
 
  • #11
r = a - h(a-b)/l
 
  • #12
Very nice!
 

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