Deriving optical- and acoustical branches

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Elekko
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On the book "Introduction to Solid State Physics" by Kittel, on page 98 he derived the roots for optical and acoustical branches for the equation:

[tex]M_1 M_2 \omega^4-2C(M_1+M_2)\omega^2+2C^2(1-cos(Ka))=0[/tex]

where the roots are:

[tex]\omega^2=2C(\frac{1}{M_1}+\frac{1}{M_2})[/tex] and
[tex]\omega^2=\frac{\frac{1}{2}C}{M_1+M_2}K^2 a^2[/tex]

I'm wondering how he actually found these roots since he skipped the details? He only mentions the trigonometric identity can be set to zero... how are the roots found?
 
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Note that these are the roots only for the limiting case of ##Ka << 1##. As Kittel states, in this case you can let ##\cos(Ka) \approx 1-\frac{1}{2}K^2a^2##.

Make this approximation and note that you have a quadratic equation in ##\omega^2##.