Deriving probability distributions

Click For Summary
SUMMARY

The discussion centers on deriving the probability distribution of a random variable X that follows a Gamma distribution, specifically \Gamma(\alpha,\beta), where \alpha is a random variable following a Binomial distribution, Bin(n,p). The correct approach to find the distribution of X involves summing over all possible values of \alpha, leading to the formula f_x(x)=\sum_{i=0}^nf(X=x|\alpha=i)f_\alpha(\alpha=i). The conversation also touches on the implications of using a Poisson distribution for \alpha, which could yield a more interesting outcome. The confusion regarding the use of summation versus integration in the context of continuous distributions is also addressed.

PREREQUISITES
  • Understanding of Gamma distribution, \Gamma(\alpha,\beta)
  • Knowledge of Binomial distribution, Bin(n,p)
  • Familiarity with conditional probability and marginal distributions
  • Basic concepts of joint probability distributions
NEXT STEPS
  • Explore the properties of Gamma distributions in detail
  • Study the implications of using Poisson distributions in probabilistic models
  • Learn about marginal and joint distributions in probability theory
  • Investigate the differences between summation and integration in probability contexts
USEFUL FOR

Statisticians, data scientists, and mathematicians interested in advanced probability theory, particularly those working with distributions and conditional probabilities.

bioman
Messages
11
Reaction score
0
Suppose I had a random variable, X, that followed a Gamma distribution.
A Gamma distribution can be defined as \Gamma(\alpha,\beta), where \alpha and \beta are the 'scale' and 'shape' parameters.
Now suppose if \alpha was a random variable, say following a binomial distribution, how would I then represent the distribution of X.

I was thinking that since the parameter \alpha now represents a random variable, the distribution of X, would simply be a binomial distribution multiplied by a Gamma distribution?
Would it be correct to do this??
 
Physics news on Phys.org
No. That is wrong.

X|\alpha is distributed as \Gamma(\alpha,\beta) and \alpha is distributed as Bin(n,p).

Therefore, f(X=x|\alpha)f_\alpha(\alpha)=f_{(x,\alpha)}(x,\alpha).

Now, to get the distribution of x, you just sum over all alpha. That is,

f_x(x)=\sum_{i=0}^nf(X=x|\alpha=i)f_\alpha(\alpha=i).

I'm not sure what this distribution is as I haven't calculated it yet. I doubt it will reduce to something familiar.

However! If alpha was distributed as poisson then it becomes an interesting distribution which is a really good exercise.

If you don't understand any of this just say so.
 
Last edited:
Thanks for the help ZioX, much appreciated!
I had a feeling I wasn't doing it right... but I'm not too sure I fully understand what you're doing. I think I get the gist of what you're doing, but just getting a bit bogged down with the mathematical notation you're using.

So firstly I presume that
X|\alpha
means "the random variable X given alpha"?
But what exactly, (in words), do you mean by
f(X=x|\alpha)f_\alpha(\alpha)=f_{(x,\alpha)}(x,\alpha)


Also, I'm curious as to why you say, it would be interesting if alpha was distributed as Poisson, as this is one of the cases I will also be looking at!
Is there some standard distribution that comes out when you use a Poisson??
 
I'm slightly confused about the answer that's given here. I needed to find the distribution of X|\alpha, where X|\alpha is distributed as a Gamma, \Gamma(\alpha,\beta), and \alpha is distributed as Bin(n,p).

The answer was to the (marginal) distribution of X, you sum over to get f_x(x)=\sum_{i=0}^nf(X=x|\alpha=i)f_\alpha(\alpha= i)

But if X is gamma distributed, and a gamma distribution is a continuous distribution, then shouldn't the above formulae be an intregal rather than a summation??
 

Similar threads

  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 11 ·
Replies
11
Views
3K