Deriving the differential equation for the underdamped case

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Tony Hau
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The formula for general oscillation is:
Handwritten equation x¨ + 2γẋ + ω₀²x = 0, with below it the definitions γ = b/(2m) and ω₀ = √(k/m).

The formula for underdamping oscillation is:
Handwritten equation x(t) = A+ e^(λ+ x) + A- e^(λ- (x)), with A+ labelled as an element of C under the first term and A- labelled as an element of C under the second.

where λ = -γ +- sqart(γ^2 - ω^2), whereas A+ and A- , as well as λ+ and λ-, are complex conjugates of each other.

After some operations, we get:
x(t) = Ae^(-γx)[e^i(θ+ωx) +e^-i(θ+ωx)], where A is the modulus of A+ and A-.

The notes of my teacher give the answer as
Handwritten line of math: x = e^(-γx)[A] cos(ωt + θ), with the cosine term's argument partly unclear.


Obviously, the complex part of e^i(θ+ωx) and e^-i(θ+ωx) cancells each other. However, the real part of the two expressions is the same. So, why isn't the final answer of x(t) Ae^(-γx)2cos(θ+ωx)?
 
Attachments
  • Handwritten equation: x double-dot + 2γ x-dot + ω0² x = 0, with below it γ = b/(2m) and ω0 = sqrt(k/m).
    1586875884559.png
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  • Handwritten equation: x double-dot + 2γ x-dot + ω0² x = 0, with γ = b/2m and ω0 = sqrt(k/m) written beneath it, with the expressions underlined.
    1586875891728.png
    1.6 KB · Views: 302
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The solution given by my teacher indeed misses a factor of 2. My guess is correct.