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 Homework Statement:

Two acoustic speakers face each other at opposite ends of a 50.0 m walkway. The speakers broadcast an identical, 66 Hz sound wave in phase. Consider a person walking along x, the straight line from one speaker to the other.
Calculate the shortest distance from the face of either speaker to a position where destructive interference causes the sound to become weak. Show your work here, and then enter your final numeric answer in the next answer box.
 Relevant Equations:

change in path distance=wave length*(m+0.5)
v sound=343 m/s
where x is the distance from one speaker
343=(66)(5.197)
wave length =5.197m
x(50x)=(5.197)(m+0.5)
I choose m=10
2x50=(5.197)(9.5)
x=0.314m?
Prof says correct answer is 1.6m tho
343=(66)(5.197)
wave length =5.197m
x(50x)=(5.197)(m+0.5)
I choose m=10
2x50=(5.197)(9.5)
x=0.314m?
Prof says correct answer is 1.6m tho