How Close to Speaker B Must You Be for Destructive Interference at 172 Hz?

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To determine the closest distance to speaker B for destructive interference at 172 Hz, the wavelength is calculated as 2 meters using the speed of sound. The condition for destructive interference requires that the path difference between the two speakers be an odd multiple of half the wavelength. Given the distance from speaker A is 8 meters, the relationship can be expressed as ΔL = d_B - d_A. By substituting the known values, it is concluded that the closest distance to speaker B for destructive interference is 1 meter. This analysis highlights the importance of understanding path differences in wave interference.
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Homework Statement



Two loudspeakers, A and B, are driven by the same amplifier and emit sinusoidal waves in phase. The frequency of the waves emitted by each speaker is 172 Hz. You are 8.00 m from speaker A. Take the speed of sound in air to be 344 m/s.

What is the closest you can be to speaker B and be at a point of destructive interference?
Express your answer in meters.

Homework Equations



f = \frac{v}{\lambda}
\frac{\Delta L}{\lambda} = .5,1.5,2.5,...

The Attempt at a Solution



\lambda = 344/172 = 2

1/2 = .5 => Ans:1m

The odd thing is that it tells you the distance you are from A but wants to know how close you can get to B but you don't know the distance between the two.

The answer is 1, since that would give you 1/2 = .5 but that seems like to me that you're 1m away from A, since we don't know how close we are to B
 
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It might help to use more explicit notation for the various distances. Let ##d_A## be your distance from speaker A and ##d_B## your distance from speaker B. You are given ##d_A = 8##m, but let's keep using the symbol ##d_A##. We can plug in numbers later.

You wrote ##\frac{\Delta L}{\lambda} = .5, 1.5, 2.5, ...##.

You can write this as ##\frac{\Delta L}{\lambda} = (n+\frac{1}{2})## where ##n = 0, 1, 2, ...##.

Can you express this equation in terms of the symbols ##d_A## and ##d_B##?
 
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