MHB Determine the diameter of the graph

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mathmari
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Hey! :o

We have the matrix $$A=\begin{pmatrix}0&1&0&0&0&0&0&1\\1&0&1&0&0&0&0&0\\0&1&0&1&0&0&0&0\\0&0&1&0&1&0&0&0\\0&0&0&1&0&1&0&0\\0&0&0&0&1&0&1&0\\0&0&0&0&0&1&0&1\\1&0&0&0&0&0&1&0\end{pmatrix}$$
and we want to determine the diameter of the graph.

For that do we have to calculate the eigenvalues? Or isn't the diameter related to the number of eigenvalues? (Wondering)
 
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mathmari said:
Hey! :o

We have the matrix $$A=\begin{pmatrix}0&1&0&0&0&0&0&1\\1&0&1&0&0&0&0&0\\0&1&0&1&0&0&0&0\\0&0&1&0&1&0&0&0\\0&0&0&1&0&1&0&0\\0&0&0&0&1&0&1&0\\0&0&0&0&0&1&0&1\\1&0&0&0&0&0&1&0\end{pmatrix}$$
and we want to determine the diameter of the graph.

For that do we have to calculate the eigenvalues? Or isn't the diameter related to the number of eigenvalues?

Hey mathmari!

I'm not aware (yet) of a relationship between eigenvalues and diameter.
But to find the diameter, we can draw the graph, and figure out its diameter from the graph can't we? (Wondering)
 
I like Serena said:
I'm not aware (yet) of a relationship between eigenvalues and diameter.
But to find the diameter, we can draw the graph, and figure out its diameter from the graph can't we? (Wondering)

Do we have the following graph?

View attachment 8334

(Wondering)
 

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    graph_matrix.png
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mathmari said:
Do we have the following graph?

Yep. (Nod)
 
I like Serena said:
Yep. (Nod)

Graph's diameter is the largest number of vertices which must be traversed in order to travel from one vertex to another, right? Is the largest number of vertices equal to 8? (Wondering)
 
mathmari said:
Graph's diameter is the largest number of vertices which must be traversed in order to travel from one vertex to another, right?

Not vertices but edges.
It's the largest possible 'distance' between 2 vertices. (Nerd)

mathmari said:
Is the largest number of vertices equal to 8?

I don't think so.
We have 8 vertices in total that are effectively arranged in a circle.
If we pick 2 of them, what is the distance (the minimum number of edges) between them? (Wondering)
 
I like Serena said:
We have 8 vertices in total that are effectively arranged in a circle.
If we pick 2 of them, what is the distance (the minimum number of edges) between them? (Wondering)

The minimum numbers of edges between two vertices is 2, right? Is this the diameter? (Wondering)
 
mathmari said:
The minimum numbers of edges between two vertices is 2, right? Is this the diameter?

Nope.
The distance between 2 vertices is the minimum number of edges between those vertices.
And the diameter is the maximum distance that we can find.

If we pick 2 neighboring edges (one edge between them), the distance is 1.
But we can also pick vertices that are further apart can't we? (Thinking)
 
I like Serena said:
Nope.
The distance between 2 vertices is the minimum number of edges between those vertices.
And the diameter is the maximum distance that we can find.

If we pick 2 neighboring edges (one edge between them), the distance is 1.
But we can also pick vertices that are further apart can't we? (Thinking)

The maximum distance between two vertices is 4, or not? (Wondering)
 
  • #10
mathmari said:
The maximum distance between two vertices is 4, or not?

Yes it is. (Nod)
 
  • #11
I like Serena said:
Yes it is. (Nod)

Ok! Thank you! (Smile)
 

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