1. The problem statement, all variables and given/known data Two shuffleboard disks of equal mass, one orange and the other yellow, are involved in an elastic, glancing collision. The yellow disk is initially at rest and is struck by the orange disk moving with a speed of 4.40 m/s. After the collision, the orange disk moves along a direction that makes an angle of 38.0° with its initial direction of motion. The velocities of the two disks are perpendicular after the collision. Determine the final speed of each disk. 2. Relevant equations p=mv 3. The attempt at a solution Well i've tried conservation of momentum, and even have this link at my disposal; i just cannot get the correct answer (probably due to basic algebra errors.) http://answerboard.cramster.com/Answer-Board/Image/200710151121116332804407123187505694.jpg Granted that my angle is 1° off, and the speed is different; I end up with a final formula of sqrt(Uo^2-Vo^2)=Vo/tan(38) =Uo^2-Vo^2 = (Vo/Tan38)^2 =Uo^2-Vo^2=Vo^2/tan(38)^2. =Tan(38)^2*Uo^2-Tan(38)^2*Vo^2=Vo^2 =tan(38)^2*^Uo^2=0.6104Vo^2 =(tan(38)^2*(4.4^2))/(0.6104)=Vo^2 =19.3602=Vo^2 =4.4=Vo Yet... that's not right, because it's the original speed and unless the yellow didn't move at all; it would be impossible. But I dont know what else to do.