Determine the final speed of each disk.

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Homework Help Overview

The problem involves two shuffleboard disks of equal mass in an elastic, glancing collision. The orange disk strikes the yellow disk, which is initially at rest, and the disks move perpendicularly after the collision. The task is to determine the final speeds of both disks.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the conservation of momentum and energy in the context of elastic collisions, suggesting the use of simultaneous equations to analyze the problem. Some participants express confusion over algebraic manipulations and the implications of the angles involved.

Discussion Status

There is ongoing exploration of the problem with various approaches being suggested, including the breakdown of momentum conservation into x and y components. Some participants are attempting to derive relationships between the velocities of the disks, while others are questioning the correctness of their algebraic steps.

Contextual Notes

Participants note potential errors in angle measurements and the implications of the disks' movements post-collision. The discussion reflects a lack of complete consensus on the correct approach and the algebraic steps involved.

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Homework Statement


Two shuffleboard disks of equal mass, one orange and the other yellow, are involved in an elastic, glancing collision. The yellow disk is initially at rest and is struck by the orange disk moving with a speed of 4.40 m/s. After the collision, the orange disk moves along a direction that makes an angle of 38.0° with its initial direction of motion. The velocities of the two disks are perpendicular after the collision. Determine the final speed of each disk.

Homework Equations


p=mv

The Attempt at a Solution


Well I've tried conservation of momentum, and even have this link at my disposal; i just cannot get the correct answer (probably due to basic algebra errors.)
http://answerboard.cramster.com/Answer-Board/Image/200710151121116332804407123187505694.jpg

Granted that my angle is 1° off, and the speed is different; I end up with a final formula of sqrt(Uo^2-Vo^2)=Vo/tan(38)
=Uo^2-Vo^2 = (Vo/Tan38)^2
=Uo^2-Vo^2=Vo^2/tan(38)^2.
=Tan(38)^2*Uo^2-Tan(38)^2*Vo^2=Vo^2
=tan(38)^2*^Uo^2=0.6104Vo^2
=(tan(38)^2*(4.4^2))/(0.6104)=Vo^2
=19.3602=Vo^2
=4.4=Vo
Yet... that's not right, because it's the original speed and unless the yellow didn't move at all; it would be impossible. But I don't know what else to do.
 
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In an elastic collision you have conservation of momentum in two perpendicular directions and conservation of energy. Easiest to pick the initial path of the orange disk as one of the directions.

That gives you 3 simultaneous equations ...
 
In oblique elastic collision conserve momentum in x and y direction separately. And apply conservation of energy.
Orange disc is moving horizontally. So its y- componet of momentum must be zero. Hence y component of vo=vosin38, and y component of vy = vysin52. To make y component zero, they must be equal and opposite, So vosin38 = vysin52 (Since mass is same it gets canceled out.) write vy in terms of vo, and put it in the equation Vy^2 = vy^2 + vo^2 and solve for vo.And hence find vy.
 
rl.bhat said:
In oblique elastic collision conserve momentum in x and y direction separately. And apply conservation of energy.
Orange disc is moving horizontally. So its y- componet of momentum must be zero. Hence y component of vo=vosin38, and y component of vy = vysin52. To make y component zero, they must be equal and opposite, So vosin38 = vysin52 (Since mass is same it gets canceled out.) write vy in terms of vo, and put it in the equation Vy^2 = vy^2 + vo^2 and solve for vo.And hence find vy.

So Vosin38=Vysin52, Vy=(vosin38)/sin52)
Vy^2 = vy^2 + vo^2 <--- Plugging it into this
(vosin38)/sin52)^2 =(vosin38)/sin52)^2 + Vo^2
Vosin38^2 = Vosin38^2 + Vo^2sin52
Vosin38^2 -Vosin38^2 -Vosin52^2 = 0
Vo(sin38^2-sin38^2-Sin52^2)=0
Vo(Sin52^2)=0
Vo=0/(sin52^2) ??
 
(vosin38)/sin52)^2 =(vosin38)/sin52)^2 + Vo^2
In the expression Vy indicates the initial velocity of the yellow disc.
So (4.4)^2 =(vosin38)/sin52)^2 + Vo^2 Now try.
 

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