Determine the smallest possible speed of the bob at A

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Homework Help Overview

The problem involves a pendulum bob of mass 0.5 kg traveling in a complete circular motion about a pivot point. Participants are tasked with determining the smallest possible speed of the bob at position A, considering two scenarios: one with a rigid rod and another with a string.

Discussion Character

  • Exploratory, Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants discuss the potential energy at different points in the pendulum's path and question the validity of their energy equations. There is an exploration of the differences in behavior between a rigid rod and a string in terms of tension and motion.

Discussion Status

The discussion is ongoing, with participants correcting each other's misunderstandings about kinetic and potential energy. Some have provided insights into the critical points of motion for both the rod and string scenarios, while others are seeking further clarification and hints for part (b) of the problem.

Contextual Notes

Participants are considering the implications of the pendulum's motion above 90 degrees and how the type of suspension (rod vs. string) affects the tension and motion of the bob. There is an emphasis on understanding the conditions under which the string remains taut.

Alexanddros81
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Homework Statement


14.34 The 0.5-kg bob of the pendulum travels a complete circle about the pivot
point O. Determine the smallest possible speed of the bob in position A if it is
suspended from (a) a rigid rod of negligible mass; and (b) a string

Fig P14_33_34.jpg

Homework Equations

The Attempt at a Solution


Pytels_Dynamics117.jpg

[/B]
I can see that the above solution is not correct.
Do I take the potential energy at A to be 0 and potential energy at ##B=mgy## where y = 4 ?

Can you check this?

Any hints for part (b)?
 

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Last edited:
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It looks like you swapped the kinetic energies of A and B. You have TA + VA on left side of one line, then it goes to 0 - 2mg on the left side of the next line. TA is -2mg, but VA should be ½mv2, and VB should be 0.

Taking point A to be y=0 is a valid strategy, as well.
 
Ah yes you're right about the swapped kinetic energies. I wasn't consentrated.
Here is the corrected solution:

Pytels_Dynamics119.jpg


Is this correct?
Any hints for part (b)?
 

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Alexanddros81 said:
Any hints for part (b)?
What's the critical point in the trajectory in case of a string ?
 
Alexanddros81 said:
Any hints for part (b)?
What is the essential difference between a rod and a string, both being massless?
 
Hi! I have found this:
https://physics.stackexchange.com/q...on-in-string-and-light-rod-in-vertical-circle

A movement of a string pendulum above 90deg will cause the string to fold up.
However, this does not happen if the pendulum bob is moving fast enough and its speed v never reaches zero when it goes up
above 90deg Then the pendulum swings in a full circle and keeps going in the same direction into the next circle.

How do interpret this to equation form?
 
For the rod uB=0 was the limiting case because the rod could take the weight of the bob.
For the string the bob has to pull on it in order to keep it stretched. The limiting case is when the tension in the string reaches zero. What determines the tension in the string at various positions ?
 

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