Determing the composition of a state

PThe conversation is discussing finding the composition of a state of a system composed of two eigenvectors. The question involves determining the probability of attaining the eigenvalues of ket v, given by the coefficients a and b in the equation. The correct values for a and b are determined to be 1/2 and (3/4)1/2 multiplied by an arbitrary phase factor. In summary, the conversation discusses finding the composition of a state of a system composed of two eigenvectors and determining the probability of attaining the eigenvalues of ket v. The values for a and b are correctly determined to be 1/2 and (3/4)1/2 multiplied by an arbitrary phase factor.
  • #1
Sekonda
207
0
Hey,

I have a question on determing the composition of a state of a system of composed of only two eigenvectors, the question is displayed below:

determinev.png


I initially assumed that the ket v was given by:

[tex]|v>=a|\omega_{1}>+b|\omega_{2}>[/tex]

Where 'a' and 'b' are constants which will determine the probability of either state. So we know the probability of the eigenvalues of ket v are given by the coefficients a and b in the equation:

[tex]\mid <v|\hat{\Omega}|v>\mid^{2}[/tex]

Where for the probability of attaining the eigenvalue ω(1) we have equation:

[tex]\frac{1}{4}=a^{4}[/tex]

Though I'm not sure this is correct, it implies

[tex]a=\frac{1}{\sqrt{2}}\: ,\: b=\sqrt{\frac{\sqrt{3}}{2}}[/tex]

I think I have made a mistake on my third equation...

Thanks for any help,
SK
 
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  • #2
P(ω1) = |<ω1|v>|2 , so: a = 1/2 and b will be (3/4)1/2 multiplied by an arbitary phase factor.
 
  • #3
Right okay, this is the other way I done it but wasn't sure which way was correct... though this answer definitely makes more sense!... obviously.

Thanks cosmic dust!
SK
 

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