Determining a Safe Distance from a GRB

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SUMMARY

The discussion focuses on calculating a "Safe Distance" from a Gamma Ray Burst (GRB) based on its total energy (E) and duration (t). The average power (P) from the GRB is derived using the formula P = E/t, with the solar constant set at approximately 1300 Watt/m². The calculation indicates that the power density at a distance R can be expressed as (1030 kg x c² x 18000)/(4π R² x 100) in W/m². This results in a conclusion that a GRB would need to be approximately 36 megalightyears away to match the solar brightness experienced on Earth, albeit only for a brief period.

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  • Understanding of Gamma Ray Bursts (GRBs) and their energy output
  • Familiarity with the concept of power density and the solar constant
  • Basic knowledge of physics formulas involving energy and distance
  • Proficiency in using mathematical constants such as π and the speed of light (c)
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  • Research the physics of Gamma Ray Bursts and their impact on surrounding space
  • Learn about the calculation of power density in astrophysics
  • Explore the implications of GRBs on cosmic distances and safety measures
  • Investigate the solar constant and its relevance in astrophysical calculations
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Astronomers, astrophysicists, and students studying high-energy astrophysics who are interested in the effects of Gamma Ray Bursts and their safe distances from Earth.

tibrorla
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Determining a "Safe Distance" from a GRB

We are given the total energy of a Gamma Ray Burst, E, over a given time t.

Therefore we can conclude that the average power is:

P = E/t

The question then asks how far one would have to be from this gamma ray burst in order for the average power from it to be equivalent to the average power from the sun's radiation at the earth.

We know that the solar constant (i.e. power released by the sun per unit area) is about 1300 Watt/m2.

This is where my problem arises, since I don't know how to relate the distance from the GRB with the average power of it and the solar constant.

Any help would be greatly appreciated.

Thanks.
 
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Just off the top of my head, I think it's about 1030 kg of matter converted into energy in about 100 sec, in two 1o cones. These cones correspond to about 1/1500 steradian, while the sphere is 4pi, so the "gain" is about 18,000x.

Thus power density at distance R is (1030 x c2 x 18000)/(4pi R2 x 100) in W/m2.

This would equal the sun brightness at the Earth about 36 megalightyears away, but only for a brief time.
 
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