MHB Determining $a_7$ with Given Conditions

  • Thread starter Thread starter anemone
  • Start date Start date
  • Tags Tags
    Conditions
Click For Summary
The sequence defined by the recurrence relation $a_{n+3}=a_{n+2}(a_{n+1}+a_n)$ leads to specific values for the integers $a_1$ through $a_7$. Given that $a_6=144$, the values of the preceding terms must be calculated to find $a_7$. By applying the recurrence relation iteratively, the values of $a_4$ and $a_5$ can be derived from earlier terms. Ultimately, the calculations yield the value of $a_7$. The final result for $a_7$ is determined through this process.
anemone
Gold Member
MHB
POTW Director
Messages
3,851
Reaction score
115
The positive integers $a_1,\,a_2,\,\cdots,a_7$ satisfy the conditions $a_6=144$, $a_{n+3}=a_{n+2}(a_{n+1}+a_n)$, where $n=1,\,2,\,3,\,4$.

Determine $a_7$.
 
Mathematics news on Phys.org
anemone said:
The positive integers $a_1,\,a_2,\,\cdots,a_7$ satisfy the conditions $a_6=144$, $a_{n+3}=a_{n+2}(a_{n+1}+a_n)$, where $n=1,\,2,\,3,\,4$.

Determine $a_7$.

144 * 24 or 3456

as
$a_4 = a_3 ( a_2 + a_1) $

$a_5 = a_4 ( a_3 + a_2) $
= $a_3 ( a_2 + a_1) ( a_3 + a_2)$

$a_6 = a_5(a_4+a_3) $
= $a_3 ( a_2 + a_1) ( a_3 + a_2)( a_3 ( a_2 + a_1) + a_3))$
= $a_3^2 ( a_2 + a_1) ( a_3 + a_2)( a_3 ( a_2 + a_1+1)$

it is product of 5 numbers of which 2 are same and 2 differ by 1

we have 144 = 2^2 * 3 * 3 * 4

so $a_3= 2$, $a_2 = 1 $ and $a_1 = 2$
using relation above we can compute $a_4= 6$, $a_5 = 18 $ and $a_6 =144$ and $a_7$ = 144* 24
 
Last edited by a moderator:
Here is a little puzzle from the book 100 Geometric Games by Pierre Berloquin. The side of a small square is one meter long and the side of a larger square one and a half meters long. One vertex of the large square is at the center of the small square. The side of the large square cuts two sides of the small square into one- third parts and two-thirds parts. What is the area where the squares overlap?

Similar threads

  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 20 ·
Replies
20
Views
2K
  • · Replies 15 ·
Replies
15
Views
3K
  • · Replies 1 ·
Replies
1
Views
1K
Replies
2
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 2 ·
Replies
2
Views
1K