The discussion focuses on calculating the mass of an anhydrous salt from a hydrate weighing 5.82 grams, which contains 62.9% water (H2O). To find the mass of the anhydrous salt, one must first determine the mass of water in the hydrate by multiplying 0.629 by 5.82 grams, resulting in approximately 3.65 grams of water. The mass of the anhydrous salt is then calculated by multiplying 0.371 by 5.82 grams, yielding approximately 2.17 grams of the anhydrous salt.
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Larrytsai said:5.82g of a Hydrate is taken. If 62.9% of H2O is contained in the Hydrate what is the mass of the anhydrous salt?
so far i got 62.9% and 37.1% and i was thinking about getting H2O in grams but i don't know how
Snazzy said:Well, if you multiply 0.371 by 5.82, I believe that would give you the mass of the anhydrous salt since 0.629 x 5.82 is the mass of the water contained in the hydrate.