Determining compound from IR and mass spec

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Using the IR full scan, I have to determine the formula and the structure of the compound. I have attached the scans. Looking at the IR scan, I see that I have an NH and a CH. So is my compound CH2N??

I also have a mass spec output for an unknown organic compound. I have to determine the structure and formula. Using the CxHy rule, I have the following:

42= C3H6
50= C4H2
67= C5H7
81= C6H9
93= C7H9
107= C8H10
138= C11H6

I am not sure what to do after this...do I just write the formulas together and that is my answer??
 
Attachments
  • Handwritten note in blue ink reads: IR Full Scan. Determine formula and structure of this compound. Below it, an IR transmittance spectrum plots %Transmittance from about -10 to 120 against wavenumbers from 4000 to 400 cm-1, with a broad dip near 3400 and sharp dips near 3000 and in the fingerprint region below 1500.
    c.jpg
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  • Mass spectrum bar chart of relative abundance (%) against m/z from 40 to 140, with labelled peaks at 42, 50, 67, 81, 93, 107 and 138, handwritten caption reading Mass Spec Output for Unknown Organic Compound, Determine Structure and Formula.
    m.jpg
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  • GC-MS output page dated 3/29/2010 with handwritten label 'GC-MS output'. Shows total ion chromatogram, extracted chromatogram, and a mass spectrum with peaks labeled near m/z 41, 55 and 138, base peak 41.
    i.jpg
    6.9 KB · Views: 680
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mimibajiduh said:
Using the IR full scan, I have to determine the formula and the structure of the compound. I have attached the scans. Looking at the IR scan, I see that I have an NH and a CH. So is my compound CH2N??

I also have a mass spec output for an unknown organic compound. I have to determine the structure and formula. Using the CxHy rule, I have the following:

42= C3H6
50= C4H2
67= C5H7
81= C6H9
93= C7H9
107= C8H10
138= C11H6

I am not sure what to do after this...do I just write the formulas together and that is my answer??

Start by looking at this, as it seems that you lack some fundmental knowledge about how mass spec works. http://www.cem.msu.edu/~reusch/VirtualText/Spectrpy/MassSpec/masspec1.htm"
 
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ok so i went to the link and i still think i did everything right. what am i doing wrong?? :(
 
Hi mimibajiduh, I looked at the spectra and they seem peculiar. Do they correspong to the same compound or to two different ones?
 
It is definite that the mass spectrum gives clue that the compound contains bromine - it follows from the fact that in nature Br is represented by two isotopes Br-79 and Br-81 respectively in almost 50:50 abundance (thus its averaged molar mass given in Periodic Table is 79,9). So if a substance contains one Br atom in its mass spectrum some of the peaks will go in pairs of pretty the same intensity and separated by 2 m/z units - just what you have at 81, 93, 107 and 138 (these correspond to molecules containing Br-81). The mass of molecule without a Br atom would then be 138-81=57 wuala! It is just what as we have in the spectrum :).
 
oh sorry for not mentioning it in my original post, they are two different ones.
 
Well it is kind of impossible to guess the structures then - see yourself: IR spectrum only gives us information about functional groups in the compound 1 and we can say that it has either NH or OH group (both give a broad peak at 3500-3000 cm-1) and from mass spectrum of the compound 2 we can say that it contains one Br atom and that is all. I hardly believe that there are people in the world who could tell what are these compound basing on spectra you give, but good luck anyway ))
 
i have attached 2 more scans of the rest of the info i have for the IR. i don't know if it will help or not.
 
Attachments
  • Infrared transmittance spectrum plotted from 4000 to 2600 cm-1, with a broad strong absorption band centred near 3400 cm-1 and sharp peaks near 2950 and 2870 cm-1; handwritten label reads IR Group frequency.
    h.jpg
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  • IR transmittance spectrum plotted as % Transmittance against Wavenumbers (cm-1) from about 1700 to 400, with handwritten label 'Finger print region 1700 - 400 cm-1' in the top right.
    e.jpg
    12.7 KB · Views: 631