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Determining Force applied so mass will stay at rest

  1. Sep 14, 2009 #1
    A weight of mass 12.5 Kg hangs from very light pulleys as shown in fig. What force must be applied to the rope so that the mass stays at rest.

    M=12.5 Kg
    W=mg
    a=g=9/8 m/s^2


    M=12.5 Kg
    W = mg = 12.5 x 9.8 = 122.5 N
    I've done this much but I have no clue what to do now. Can someone plz help me out?
     

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    Last edited: Sep 14, 2009
  2. jcsd
  3. Sep 14, 2009 #2
    the figure doesn't show, therefore i am unable to help u, if u want u can send it to my email so i can try it. its [email address deleted by moderator]
     
    Last edited by a moderator: Dec 10, 2010
  4. Sep 14, 2009 #3
  5. Sep 14, 2009 #4

    kuruman

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    Can you find the tension in each part of the rope and relate it to the weight you have calculated? Hint: Draw a free body diagram of the pulley that is directly over the hanging mass. If that pulley is at rest, what must be true about the forces acting on it?
     
    Last edited: Sep 14, 2009
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