MHB Determining if the sequence convergers or diverges

  • Thread starter Thread starter shamieh
  • Start date Start date
  • Tags Tags
    Sequence
Click For Summary
The sequence $$\frac{tan^{-1} n}{n}$$ is analyzed for convergence or divergence. As n approaches infinity, the arctangent function approaches $$\frac{\pi}{2}$$, while n increases without bound. This results in the limit of the sequence being $$\frac{\frac{\pi}{2}}{n}$$, which approaches 0. Therefore, the sequence converges to 0. The conclusion is that the sequence converges.
shamieh
Messages
538
Reaction score
0
Determine if the sequence converges ot diverges. If it converges, find the limit

$$\frac{tan^{-1} n}{n}$$

So I'm thinking that I can say tan inverse is $$\frac{\frac{\pi}{2}}{n}$$ as n--> infinity is going to be some number over infinity = 0? so therefore it converges to 0?
 
Physics news on Phys.org
shamieh said:
Determine if the sequence converges ot diverges. If it converges, find the limit

$$\frac{tan^{-1} n}{n}$$

So I'm thinking that I can say tan inverse is $$\frac{\frac{\pi}{2}}{n}$$ as n--> infinity is going to be some number over infinity = 0? so therefore it converges to 0?

Yes, since your top goes to a finite value and your bottom gets infinitely larger, the limit of this function is 0. So yes your sequence converges to 0.
 
There are probably loads of proofs of this online, but I do not want to cheat. Here is my attempt: Convexity says that $$f(\lambda a + (1-\lambda)b) \leq \lambda f(a) + (1-\lambda) f(b)$$ $$f(b + \lambda(a-b)) \leq f(b) + \lambda (f(a) - f(b))$$ We know from the intermediate value theorem that there exists a ##c \in (b,a)## such that $$\frac{f(a) - f(b)}{a-b} = f'(c).$$ Hence $$f(b + \lambda(a-b)) \leq f(b) + \lambda (a - b) f'(c))$$ $$\frac{f(b + \lambda(a-b)) - f(b)}{\lambda(a-b)}...

Similar threads

  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 17 ·
Replies
17
Views
5K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 3 ·
Replies
3
Views
3K
  • · Replies 6 ·
Replies
6
Views
4K
  • · Replies 11 ·
Replies
11
Views
5K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 11 ·
Replies
11
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K