MHB Determining if the sequence convergers or diverges

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The sequence $$\frac{tan^{-1} n}{n}$$ is analyzed for convergence or divergence. As n approaches infinity, the arctangent function approaches $$\frac{\pi}{2}$$, while n increases without bound. This results in the limit of the sequence being $$\frac{\frac{\pi}{2}}{n}$$, which approaches 0. Therefore, the sequence converges to 0. The conclusion is that the sequence converges.
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Determine if the sequence converges ot diverges. If it converges, find the limit

$$\frac{tan^{-1} n}{n}$$

So I'm thinking that I can say tan inverse is $$\frac{\frac{\pi}{2}}{n}$$ as n--> infinity is going to be some number over infinity = 0? so therefore it converges to 0?
 
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shamieh said:
Determine if the sequence converges ot diverges. If it converges, find the limit

$$\frac{tan^{-1} n}{n}$$

So I'm thinking that I can say tan inverse is $$\frac{\frac{\pi}{2}}{n}$$ as n--> infinity is going to be some number over infinity = 0? so therefore it converges to 0?

Yes, since your top goes to a finite value and your bottom gets infinitely larger, the limit of this function is 0. So yes your sequence converges to 0.
 
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