Determining if the sequence convergers or diverges

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SUMMARY

The sequence defined by the expression $$\frac{\tan^{-1} n}{n}$$ converges to 0 as n approaches infinity. The reasoning is based on the fact that the arctangent function approaches $$\frac{\pi}{2}$$, while n increases without bound, leading to the limit being a finite value divided by an infinitely large value. Thus, the sequence converges definitively to 0.

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  • Understanding of limits in calculus
  • Familiarity with the arctangent function, specifically $$\tan^{-1}$$
  • Knowledge of sequences and series convergence
  • Basic algebraic manipulation skills
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  • Explore other sequences and their limits, such as $$\frac{\sin n}{n}$$
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shamieh
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Determine if the sequence converges ot diverges. If it converges, find the limit

$$\frac{tan^{-1} n}{n}$$

So I'm thinking that I can say tan inverse is $$\frac{\frac{\pi}{2}}{n}$$ as n--> infinity is going to be some number over infinity = 0? so therefore it converges to 0?
 
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shamieh said:
Determine if the sequence converges ot diverges. If it converges, find the limit

$$\frac{tan^{-1} n}{n}$$

So I'm thinking that I can say tan inverse is $$\frac{\frac{\pi}{2}}{n}$$ as n--> infinity is going to be some number over infinity = 0? so therefore it converges to 0?

Yes, since your top goes to a finite value and your bottom gets infinitely larger, the limit of this function is 0. So yes your sequence converges to 0.
 

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