Determining possible trajectories (Classical Mechanics)

In summary, the question requests the determination of possible trajectories for a particle with constant velocity and angular momentum. It can be inferred that the direction of the velocity may change, but the speed remains constant. By differentiating the equation for angular momentum, it can be determined that the net torque and force are zero. This implies that the particle may follow a linear path. The question may require further mathematical development to graph the trajectories in phase space.
  • #1
MrCreamer
6
0

Homework Statement



Determine possible trajectories for particle with constant magnitude of velocity |[itex]\dot{\vec{r}}[/itex]| = v0 and constant angular momentum [itex]\vec{L}[/itex] = [itex]\vec{L}[/itex]0

Homework Equations



|[itex]\dot{\vec{r}}[/itex]| = v0
[itex]\vec{L}[/itex] = [itex]\vec{L}[/itex]0

The Attempt at a Solution



I know that L dot is zero and thereby the torque is zero. My intuition tells me that the possibly trajectories would be circles but mathematically, I am not sure where to start.
 
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  • #2
Look at he definition of L. Perhaps the time derivative of that tells you something
 
  • #3
Well, as I said, if [itex]\dot{\vec{L}}[/itex] = 0, then the net torque and net force are zero. The constant velocity magnitude implies that the direction of the velocity vector can change but the speed would remain constant.

If F is zero, then you have

m[itex]\ddot{x}[/itex] = 0

Which implies that x(t) is of some linear form:

x(t) = at + b, where a = v[itex]_{0}[/itex] and b = x[itex]_{0}[/itex].

I'm assuming the question requires the graphing of the trajectories in phase space and hence would require some form of mathematical development in terms of the energy of the system.
 
  • #4
I think BvU meant for you to differentiate ##\vec{L} = \vec{r}\times\vec{F}## and to interpret the result.

By the way, your inference that ##\dot{\vec{L}} = 0## implies ##\vec{F}=0## is not correct.
 
  • #5
I meant: differentiate ##\vec L = \vec r \times \vec p## wrt time, knowing ##\vec p = m\dot{\vec r}##. Don't venture into x and y because you have everything you need in polar coordinates.
 

FAQ: Determining possible trajectories (Classical Mechanics)

1. What is the purpose of determining possible trajectories in classical mechanics?

The purpose of determining possible trajectories in classical mechanics is to predict the motion of objects based on the laws of motion and initial conditions. This allows us to understand and analyze the behavior of physical systems, such as projectiles, planets, and particles.

2. How are possible trajectories calculated in classical mechanics?

Possible trajectories in classical mechanics are calculated using mathematical equations derived from Newton's laws of motion. These equations take into account factors such as initial position, velocity, and acceleration to determine the path of an object's motion.

3. What assumptions are made when determining possible trajectories in classical mechanics?

When determining possible trajectories in classical mechanics, we assume that there are no external forces acting on the object other than the ones we are considering. We also assume that the object is moving in a vacuum, without any air resistance or friction.

4. Can classical mechanics accurately predict the motion of all objects?

No, classical mechanics is limited in its ability to accurately predict the motion of objects at very small scales, such as subatomic particles, or at very high speeds, such as objects moving close to the speed of light. In these cases, we must use other theories, such as quantum mechanics or relativity.

5. How does the shape of an object affect its trajectory in classical mechanics?

The shape of an object can affect its trajectory in classical mechanics because it can impact factors such as air resistance and gravitational pull. For example, a streamlined object will experience less air resistance and therefore have a different trajectory than a more irregularly shaped object. Additionally, the mass distribution of an object can also affect its trajectory.

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