MHB Determining similarity of plane figures

[MathIsHard123]

really need help on this I learned it but forgot how to do it. thanks if you reply with explanation

 

[mathbalarka]

Two polygons in Euclidean geometry are called similar when, roughly speaking, one can be resized (zoomed in and zoomed out) to obtain another.

This is essentially equivalent to saying (are you familiar with the geometric proof of this) that if you have two polygons with sides labeled $AB, BC, CD, \cdots$ and $A'B', B'C', C'D', \cdots$ and the angles labelled $\alpha, \beta, \gamma, \cdots$ and $\alpha', \beta', \gamma', \cdots$ in the same order, then $$\frac{AB}{A'B'} = \frac{BC}{B'C'} = \frac{CD}{C'D'} = \cdots$$ $$\alpha = \alpha', \beta = \beta', \gamma = \gamma', \cdots$$

What can you say about the polygons you are given? Can you use the fact above?

 

[Evgeny.Makarov]

Two polygons in Euclidean geometry are called similar when, roughly speaking, one can be resized (zoomed in and zoomed out) to obtain another.

This is essentially equivalent to saying (are you familiar with the geometric proof of this) that if you have two polygons with sides labeled $AB, BC, CD, \cdots$ and $A'B', B'C', C'D', \cdots$ in the same order, then $$\frac{AB}{A'B'} = \frac{BC}{B'C'} = \frac{CD}{C'D'} = \cdots$$

For triangles, this is indeed equivalent. For polygons with more than three sides, the fact that sides are proportional is necessary for the polygons to be similar, but it is not sufficient.

 

[anemone]

Hello MathIsHard123 (Wave) and welcome to MHB!I have re-titled your thread so that it reflects the nature of the question being asked. A title such as "Math Help" tells us no more than we already know...when our users view the thread listing, it is best if the titles give some indication of the type of question posted. This makes MHB more efficient for our users, and ensures you get the most prompt help possible.:)

 

[mathbalarka]

For triangles, this is indeed equivalent. For polygons with more than three sides, the fact that sides are proportional is necessary for the polygons to be similar, but it is not sufficient.

Fair enough, otherwise a Rhombus and a square would be similar. The diagonals must be similar too, but that fact isn't needed here. I evidently didn't see the angles marked in the image. :p