Determining terminal voltage, field current,etc.

  • Thread starter Thread starter Vladi
  • Start date Start date
  • Tags Tags
    Field Voltage
Click For Summary

Homework Help Overview

The problem involves a shunt generator, focusing on calculating terminal voltage, field current, and power delivered to an external circuit based on given parameters such as induced emf and resistances.

Discussion Character

  • Exploratory, Conceptual clarification, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the relationship between terminal voltage and generated emf, questioning the need for sign changes in the armature current equation. There are inquiries about the current distribution among the armature, field, and external circuit.

Discussion Status

Some participants have provided guidance on the circuit diagram and the implications of current flow in a DC generator. Multiple interpretations regarding the equations and their signs are being explored, with no explicit consensus reached yet.

Contextual Notes

Participants are considering the constraints of the problem, such as the relationship between terminal voltage and generated emf, and the application of Kirchhoff's Current Law (KCL) in the context of the generator's operation.

Vladi

Homework Statement


The emf induced in the armature of a shunt generator is 596 V. The armature resistance is 0.100 Ω. (a) Compute the terminal voltage when the armature current is 460 A. (b) The field resistance is 110 Ω. Determine the field current, and the current and power delivered to the external circuit.

Homework Equations


Armature Current= (Line voltage - Back emf)/Armature resistance
R=V/I
P=(V)(I)

The Attempt at a Solution


I felt good about my work until I checked the key. Where did I go wrong?
page 1.jpg
page 2.jpg
 
Physics news on Phys.org
A DC generator's terminal voltage can not be greater than its generated emf (induced).
Draw the circuit diagram for shunt generator. Your armature current equation needs a couple of sign changes.
 
cnh1995 said:
A DC generator's terminal voltage can not be greater than its generated emf (induced).
Draw the circuit diagram for shunt generator. Your armature current equation needs a couple of sign changes.
I drew a circuit diagram and re-did the problem. I got the right answers, but I still have a few questions. Are the sign changes only
necessary in order to ensure that the terminal voltage was less than the generated emf? Why is the armature's current equal to the sum of the field's and external circuit's current? I wrote down that was true because I found solutions to a similar problem that stated this fact. Thank you for your time.
1.jpg
2.jpg
 
Vladi said:
Are the sign changes only
necessary in order to ensure that the terminal voltage was less than the generated emf?
DC generator supplies power to the external circuit, hence, armature current flows out of the armature winding through its positive terminal.
Vladi said:
Why is the armature's current equal to the sum of the field's and external circuit's current?
Because the field is current is supplied by the generator terminal voltage. Hence, as per KCL, the armature current splits into field current and external circuit current.
 
  • Like
Likes   Reactions: Vladi
cnh1995 said:
DC generator supplies power to the external circuit, hence, armature current flows out of the armature winding through its positive terminal.

Because the field is current is supplied by the generator terminal voltage. Hence, as per KCL, the armature current splits into field current and external circuit current.
Thank you for all your help.
 

Similar threads

  • · Replies 10 ·
Replies
10
Views
2K
  • · Replies 9 ·
Replies
9
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 1 ·
Replies
1
Views
878
  • · Replies 1 ·
Replies
1
Views
833
  • · Replies 2 ·
Replies
2
Views
752
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 13 ·
Replies
13
Views
3K
  • · Replies 4 ·
Replies
4
Views
1K
  • · Replies 2 ·
Replies
2
Views
2K