1. The problem statement, all variables and given/known data 2 crates, 75kg(crate x) and 110kg(crate z) are in contact and at rest on a horizontal surface. A 620N force is applied on crate x . If the coefficient of friction is 0.15, calculate: a.) the acceleration of the system b.)the force that each crate exerts on each other c.) repeat when the crates reversed 2. Relevant equations Msys = (massx)+(massz) Force = mass(acceleration) 3. The attempt at a solution a. Msys = 75kg + 110kg = 185kg 620N = 185kg(a) a = 3.35m/s2 b. cratex= 75kg(3.35m/s2) =251.25N cratez= 110(3.35m/s2) =368.5N c. cratez= 110(3.35m/s2) =368.5N cratex= 75kg(3.35m/s2) =251.25N thanks in advance!