How to Diagonalize a Hamiltonian with Fermion Operators?

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SUMMARY

The discussion focuses on diagonalizing a Hamiltonian for a 1D electron system using fermion operators, specifically the annihilation and creation operators a, a†, b, and b†. The Hamiltonian is expressed as H = v_F∑_{k>0}k(a†_ka_k - b†_kb_k) + Δ∑_k(b†_{k-k_F}a_{k+k_F} + a†_{k+k_F}b_{k-k_F}), where v_F and Δ are constants. The correct spectrum is derived as E = v_Fk_F ± v_F(Δ² + k²)^{1/2}, ensuring unit consistency in the terms involved. The user attempts to define operators forming an su(2) algebra to facilitate the diagonalization process.

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Homework Statement


I am trying to solve a problem of 1D electron system.
Given a,a^\dagger,b,b^\dagger annihilation and creation operator which satisfy the fermion commutation relations diagonalize the following hamiltonian:

H=v_F\sum_{k>0}k(a^\dagger_ka_k-b^\dagger_kb_k)+\Delta\sum_k(b^\dagger_{k-k_F}a_{k+k_F}+a^\dagger_{k+k_F}b_{k-k_F})

where v_F,\Delta are c-numbers.

Prove that the spectrum is given by:
E=v_Fk_F\pm v_F(\Delta^2+k^2)^{1/2}

2. The attempt at a solution
I try to define the following operators (that form an su(2) algebra):
J_3=\frac{1}{2}(a^\dagger_{k+k_F}a_{k+k_F}-b^\dagger_{k-k_F}b_{k-k_F})
J_+=a^\dagger_{k+k_F}b_{k-k_F}
J_-=b^\dagger_{k-k_F}a_{k+k_F}
and to calculate the adjoint action but I don't know how to continue.
Please help me, thank you.
 
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The spectrum cannot be given by
E=v_Fk_F\pm v_F(\Delta^2+k^2)^{1/2}
because the units of \Delta and k are not the same. I tried rewriting the first term (linear kinetic energy) using operators shifted by k_F and then diagonalizing it, and I got
E=\frac{1}{2} (v_F k_F \pm (v_F^2 k^2 + 4\Delta^2)^{1/2})
Still may not be correct, but at least the units match.
 

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