Dice probability

  • #1

Main Question or Discussion Point

Say you roll a dice twice.You want to calculate the probablity of getting both dice to land on 3. Using the formula for combinations: the total number of combinations is 21. so is the probabilty of getting a 3 on both dice 1 /21 ?
 

Answers and Replies

  • #2
pwsnafu
Science Advisor
1,080
85
The probability of rolling a three on a six sided die is ##\frac16##. Doing it twice is ##\frac{1}{6} \cdot \frac{1}{6} = \frac{1}{36}##
 
  • #3
explain

I don't see the logic
how is it permuation formula(combination formula ).
What is wrong with my method?
 
  • #4
269
24
Whatever formula you have in mind, but there are 36 possible outcomes: [itex]\{(1,1), (1,2), (1,3), (1,4), (1,5), (1,6), (2,1), (2,2), (2,3), (2,4), (2,5), (2,6), (3,1), (3,2), (3,3), (3,4), (3,5), (3,6), (4,1), (4,2), (4,3), (4,4), (4,5), (4,6), (5,1), (5,2), (5,3), (5,4), (5,5), (5,6), (6,1), (6,2), (6,3), (6,4), (6,5), (6,6)\}[/itex]
If each of these seems equally likely to you, then the answer is [itex]\frac1{36}[/itex].
 
  • Like
Likes 1 person
  • #5
269
24
I'm guessing your method was to plug in "6 choose 2", which is the formula that tells you how many ways to pick a pair of people from a collection of 6 people. That doesn't describe the situation you named.
 
  • #6
tiny-tim
Science Advisor
Homework Helper
25,832
250
hi new_at_math! :smile:
Say you roll a dice twice.You want to calculate the probablity of getting both dice to land on 3. Using the formula for combinations: the total number of combinations is 21.
no, you're completely misunderstanding what combinations are for :redface:

21 is the number of different results you can get from two seven-sided dice if you're not allowed doubles …

12 13 14 15 16 17 23 24 25 26 27 34 35 36 37 45 46 47 56 57 67 …

start again: write out the possible combinations for a 3 (you did mean 3-total?) :smile:
 
  • #7
I get it now it was a permutation with repetition;my bad.
 
  • #8
269
24
Say you roll a dice twice.You want to calculate the probablity of getting both dice to land on 3.
I don't believe any formula with the word "permutation" or the word "combination" is an effective way to approach this problem.
 
  • #10
HallsofIvy
Science Advisor
Homework Helper
41,833
955
Say you roll a dice twice.
You roll a die twice. (Or you roll two dice.) "Dice" is the plural of "die".


You want to calculate the probablity of getting both dice to land on 3. Using the formula for combinations: the total number of combinations is 21. so is the probabilty of getting a 3 on both dice 1 /21 ?
Another way of looking at this is that if "A" and "B" are independent events, then the probability of "A and B" is the probability of A times the probability of B.

There are 6 faces on a die, one of which is a "3". As long as the faces are all equally likely to come up, the probability of a "3" is 1/6. The second roll of the die is independent of the first so the probability that both will come up "3" is (1/6)(1/6)= 1/36.
 
Last edited by a moderator:

Related Threads on Dice probability

  • Last Post
Replies
3
Views
2K
  • Last Post
Replies
2
Views
4K
  • Last Post
Replies
16
Views
345
  • Last Post
Replies
2
Views
1K
  • Last Post
Replies
0
Views
6K
  • Last Post
Replies
10
Views
7K
  • Last Post
Replies
6
Views
2K
Replies
3
Views
5K
  • Last Post
Replies
11
Views
1K
Replies
4
Views
806
Top