Calculating the Force of Gravity on a 1-kg Mass at Twice Earth's Radius

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SUMMARY

The force of gravity on a 1-kg mass located at twice Earth's radius (1.28 x 10^7 m) is calculated using the gravitational force equation F = G(M1*M2)/(r^2). With G = 6.67 x 10^-11 N*m^2/kg^2, the mass of Earth as 6 x 10^24 kg, and the distance as 1.28 x 10^7 m, the resulting gravitational force is 2.4 N. This calculation confirms the attraction force between the object and Earth at this specific distance.

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vitaly
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Calculate the force of gravity on a 1-kg mass if it were 6.4 x 10^6 m above Earth's surface (twice Earth's radius).

Known: Mass of object 1 = 1 kg
Mass of Earth = 6 x 10^24 kg
Earth's radius = 6.4 x 10^6 m; 2x this is 1.28 x 10^7 m
G = 6.67 x 10^-11 N*m^2/kg^2

Equation: F = G(Mass of object)(Mass of Earth)/(Distance)^2
= (6.67 x 10^-11 N*m^2/kg^2)(1 kg)(6 x 10^24 kg)/(1.28 x10 ^7 m)^2
= 2.4 N
 
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yes you did it right

it's simply asking you for hte attraction force between the object and earth, really.
 
Ok, thank you for checking.
 

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