Did I get it wrong? (transformation problem)

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Homework Help Overview

The discussion revolves around a transformation problem involving the graph of the function y=x³ and the point P(2,8). The original poster expresses confusion about how the point P is affected when the graph is expanded horizontally by a factor of 3 about the line x=4.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • The original poster initially considers shifting the graph before applying the transformation but later realizes this may not be the correct order. Another participant suggests interpreting the transformation as multiplying the distance from x=4 by 3, leading to a different point.

Discussion Status

Participants are exploring different interpretations of the transformation process. One participant expresses understanding after considering another's explanation, indicating that some clarity has been achieved, though no consensus on the correct answer has been reached.

Contextual Notes

The original poster mentions feeling frustrated about the transformation question being the only one they struggled with on the exam. There is also a question about the reasoning behind ruling out one of the answer choices quickly.

dontdisturbmycircles
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Homework Statement



I just got back from writing my grade 12 math final and I figure I did really well. There was only one question that stumped me, and it was freaking stupid, too. So the problem was this:

There was a picture of [tex]y=x^{3}[/tex] and the points P(2,8) was labelled. The question was where does the point P go if the graph is expanded horizontally by a factor of 3 about the line x=4... What the hell did they mean? I thought they meant that you first shift the graph over 4 places to x=4 and then you would apply the transformation, the point would end up being Q(10,8) but that wasn't even on there.

Here were my choices...

A.(8,8)
B.(14/3,8) (I think)
C.(10/3,8)
D.(-2,8)

I ruled out D pretty quickly and went with A... but it didn't make any sense. Did I get it wrong? :cry:

Pretty sad the the only question that stumped me was a transformation question... :eek:

Homework Equations





The Attempt at a Solution

 
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Woops, I meant you would apply the transformation and then shift it over, wrong way around. But anyways, both methods were fruitless.
 
dontdisturbmycircles said:

Homework Statement



I just got back from writing my grade 12 math final and I figure I did really well. There was only one question that stumped me, and it was freaking stupid, too. So the problem was this:

There was a picture of [tex]y=x^{3}[/tex] and the points P(2,8) was labelled. The question was where does the point P go if the graph is expanded horizontally by a factor of 3 about the line x=4... What the hell did they mean? I thought they meant that you first shift the graph over 4 places to x=4 and then you would apply the transformation, the point would end up being Q(10,8) but that wasn't even on there.
I would interpret that to mean that the point's distance from x= 4 is multiplied by 3- if x is larger than 4, then it moves to the right 3 times that distance. If x is less than 4, then it moves to the left 3 times that distance.

In this example, 2< 4 and the distance from 2 to 4 is 4-2= 2. (2, 8) is transformed to a point with x< 4 and 4- x= 3(2)= 6 so x= 4- 6= -2. Since the change is only horizontal, y does not change.
(2, 8) is transformed to (-2, 8)

Here were my choices...

A.(8,8)
B.(14/3,8) (I think)
C.(10/3,8)
D.(-2,8)

I ruled out D pretty quickly and went with A... but it didn't make any sense. Did I get it wrong? :cry:

Pretty sad the the only question that stumped me was a transformation question... :eek:
How did you rule out D "pretty quickly"?
 
That sounds like a good interpretation. Definitely makes sense to me now that I think about it. I figured that no positive stretch is going to result in a positive point moving to the left... But I was wrong!

Thankyou for clearing that up, I understand the concept now.
 

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