1. The problem statement, all variables and given/known data A diesel engine which drives a generator has an output of 60 hp operating at a n=31%. Then generator has a n=79% and supploes a load circuit at 240 V. The diesel engine uses light fuel oil (LFO) with a calorific value of 19,600 BTU/lb. Calculate: 1. The generator output in kW 2. The current in the generator 3. the fuel consumption in gallons per day (weight of LFO=8.3lb/gal; 1BTU=1055J) 2. Relevant equations P=IV 3. The attempt at a solution I am not sure if this is correct, its out of the book so I don't know. For the first part i simple turned the 60hp into W knowing that 1 hp=745.7 W, so that gave me 44,742 W. I then multiplied that number by .79(the effecicency of the generator to get 35,346.2W which is equal to 35.35 kW. Is this correct? For the second part I simpled used P=IV plugging in P=35.35kW, and V=240 to get 147.27 A. I believe this part is right aslong as the first part is right. The third and final part i used what I learned in chemistry, stochiometry in a way, 35,346.2 W *(1 BTU/1055 W)*(1 lb/19,600 BTU)*(1 gal/8.3 lb)=2.06x10^-4 gals everything except gals cancels, but the question asks gals/day but i don't know how I would do that.... Thanks for your help!