Difference between pseudorapidity and rapidity

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Discussion Overview

The discussion revolves around the differences between pseudorapidity and rapidity in the context of high-energy accelerators. Participants explore the definitions, mathematical formulations, and physical interpretations of both concepts.

Discussion Character

  • Exploratory
  • Technical explanation
  • Debate/contested

Main Points Raised

  • Some participants assert that rapidity is a type of "velocity" while pseudorapidity is described as a type of "angle" related to detector positioning.
  • One participant expresses confusion regarding the interpretation of rapidity as a velocity, questioning the units derived from its formula.
  • Another participant references the relationship between rapidity and spatial velocity, noting that rapidity is a Minkowski-angle in spacetime.
  • There is a question about the physical description of rapidity in the detector and whether the angle in the pseudorapidity formula corresponds to rapidity.
  • One participant discusses the mathematical relationships involving rapidity, energy, and momentum, suggesting that pseudorapidity is also a form of rapidity under certain conditions.
  • Clarification is provided that the angle in the pseudorapidity formula refers to the angle of deviation from the beam center, not rapidity itself.

Areas of Agreement / Disagreement

Participants do not reach a consensus on the definitions and interpretations of pseudorapidity and rapidity, with multiple competing views and ongoing questions about their relationships and applications.

Contextual Notes

Some participants highlight limitations in understanding due to the complexity of the concepts and the mathematical formulations involved. There is also mention of specific references that may clarify the definitions further.

indigojoker
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I was wondering what the different between pseudorapidity and rapidity was (pertaining to a high energy accelerator). I know know pesudorapidity is but not sure what rapidity is.
 
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rapidity is a type of "velocity" while pseudorapidity is a type of "angle" that tells me where I am in the detector. That doesn't make any sense at all to me because I don't think one can get m/s from the rapidity formula [tex]y = \frac{1}{2} ln \left( \frac{E+p_{z}}{E-p_{z}} \right)[/tex]
 
indigojoker said:
rapidity is a type of "velocity" while pseudorapidity is a type of "angle" that tells me where I am in the detector. That doesn't make any sense at all to me because I don't think one can get m/s from the rapidity formula [tex]y = \frac{1}{2} ln \left( \frac{E+p_{z}}{E-p_{z}} \right)[/tex]
Rapidity [tex]\theta[/tex] is a [Minkowski-]angle in spacetime [not space], whose hyperbolic-tangent is related to the spatial-velocity [in space] by:
[tex]\tanh \theta = \displaystyle\frac{v}{c} = \beta[/tex]

Have you seen
http://pdg.lbl.gov/2007/reviews/kinemarpp.pdf
38. Kinematics, p. 7 , eqns. 38.35-38.37 [where rapidity is called [itex]y[/itex] instead]?
Note (as noted on p.1 of that section) "units are used in which [tex]\hbar=c=1[/tex]", which not the best way to say it... but it works.
 
so where in the detector does rapidity physically describe?

pseudorapidity is described by:
[tex]\eta=-ln \left( tan \left( \frac{\theta}{2} \right) \right)[/tex]

is the theta in this formula rapidity?
 
indigojoker said:
I was wondering what the different between pseudorapidity and rapidity was (pertaining to a high energy accelerator). I know know pesudorapidity is but not sure what rapidity is.

Both are rapidities, where the rapidity [itex]\theta[/itex] is just a measurement of speed:

[tex]v/c\ =\ \tanh(\theta)[/tex]

The rapidity is zero when v=0, while the rapidity becomes infinite if v=c.
Rapidity is often used to calculate the energy and momentum of a particle:

[tex]E\ =\ \gamma m c^2\ =\ \frac{mc^2}{\sqrt{1-v^2/c^2}}\ =\ \cosh(\theta) mc^2[/tex]

[tex]p\ =\ \gamma m v\ =\ \frac{mv}{\sqrt{1-v^2/c^2}}\ = \sinh(\theta) m[/tex]

Pseudorapidity is a rapidity also: If a particle has a small deviation from
the center path of a beam expressed by an angle [itex]\alpha[/itex], and the beam is
assumed to approach the speed of light, then the particle will have a speed
component in the forward direction of the beam which is lower than c.

This speed depends on the angle of deviation and is given by the formula
you quoted. This is a rapidity, To get the speed of the particle you can
simply apply the first formula given above.

So, this is then the speed-component of the particle in the forward
direction of the beam. The total speed of the particle approaches c
a well, like the other particles of the beam.

indigojoker said:
pseudorapidity is described by:
[tex]\eta=-ln \left( tan \left( \frac{\theta}{2} \right) \right)[/tex]

is the theta in this formula rapidity?

No, it's the angle of deviation of the center of the beam.


Regards, Hans
 

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