Solve Height Puzzle: Find Davina's Height Using Algebraic Equations

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Homework Help Overview

The problem involves determining the height of Davina based on the relative heights of three individuals: Pritesh, Davina, and Alicia. It is stated that Pritesh is taller than Davina, who is taller than Alicia, with the height differences being equal and the total height summing to 300 cm.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants explore algebraic equations to express the relationships between the heights, questioning how to derive Davina's height without relying on trial and error.

Discussion Status

Several participants have provided algebraic formulations and substitutions, leading to a consensus that Davina's height is 100 cm. However, there is ongoing discussion about the need for additional equations to determine the heights of Pritesh and Alicia, indicating that while Davina's height is established, the overall problem remains partially unresolved.

Contextual Notes

Participants note the challenge of solving for three unknowns with only two equations, highlighting the limitations of the information provided in the problem statement.

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Homework Statement



Pritesh is taller than Davina who is taller than Alicia. The difference in height between Pritesh and Davina is the same as the difference in height between Davina and Alicia. The total of their heights is 300 cm. How tall is Davina?

Homework Equations



Now trial and error gives me Alicia = 50cm, Davina = 100cm and Pritesh = 150cm as the difference between them is 50cm

The Attempt at a Solution



How could I do this problem using only algebra, rather than what I did with trial and error?
 
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Natasha1 said:

Homework Statement



Pritesh is taller than Davina who is taller than Alicia. The difference in height between Pritesh and Davina is the same as the difference in height between Davina and Alicia. The total of their heights is 300 cm. How tall is Davina?

Homework Equations



Now trial and error gives me Alicia = 50cm, Davina = 100cm and Pritesh = 150cm as the difference between them is 50cm

The Attempt at a Solution



How could I do this problem using only algebra, rather than what I did with trial and error?
Maybe P+D+A = 300

P-D = D-A

Are those two equations enough to get the solution? :smile:
 
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P = 2D - A

So substituting gives
2D - A + D + A = 300
3D = 300
D = 100

How do I get P and A?
 
Hi, let's write these info:

P+A+D= 300
D-P=A-D

You need D

Look at the second equation, you can write it as: 2D= P+A , that's amazing

Look at the first : (P+A)+D= 300

Can you see it?
 
Natasha1 said:
P = 2D - A

So substituting gives
2D - A + D + A = 300
3D = 300
D = 100

How do I get P and A?

You can't, you need another equation, but you only need D
 
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D-100=A-100

So D = A which is wrong??
 
Cozma Alex said:
2D= P+A
Cozma Alex said:
(P+A)+D= 300
Natasha1 said:
D-100=A-100
Just re-check your algebra... :smile:
 
P-D = D-A
so
P - 100 = 100 - A
P = 200 - A
A = 200 - P

Is this correct?
 
Natasha1 said:
Is this correct?
Does it give the right answer?
 
  • #10
Natasha1 said:
P = 2D - A

So substituting gives
2D - A + D + A = 300
3D = 300
D = 100
So Davina is 100 cm tall, that is correct.
Natasha1 said:
How do I get P and A?
You don't have enough information to answer that question. That's why you are only asked how tall Davina is.
 
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  • #11
Can you remember a technique that allows you to deal with more than one unknown quantity, and can you recognize the quantity you do not need to answer this question?

Hint: look at your algebra, it'll be easier to think about this algebraically than from just reading the problem text (which is what you're asking for, correct?).
 
  • #12
Natasha1 said:

Homework Statement



Pritesh is taller than Davina who is taller than Alicia.
Let P be the Pritesh's height, in cm, D be Davina's height in cm., and A be Alicia's height in cm.

The difference in height between Pritesh and Davina is the same as the difference in height between Davina and Alicia.
So P- D= D- A.

The total of their heights is 300 cm. How tall is Davina?
And A+ D+ P= 300. That give two equations, P- D= D- A and A+ D+ P= 300 to solve for three unknowns. That is not enough information. We need one more equation. We Could write P- D- A as 2D= P+ A and replace "P+ A" in the second equation by 2P to get 2D+ D= 3D= 300 to get D= 100. But putting D= 100 in either of the two equations gives P- 100= 100- A so that A+ P= 200.

2. Homework Equations
Now trial and error gives me Alicia = 50cm, Davina = 100cm and Pritesh = 150cm as the difference between them is 50cm.
Yes, that is one solution. But taking, say, A= 40, P= 200- 40= 160 also satisfies A+ P= 200 so also satisfies "P- D= 160- 100= 60" and "D- A= 100- 40= 60". Or taking A= 25, P= 200- 25= 175, which also satisfies A+ P= 200 as well as "P- D= 175- 100= 75" and "D- A= 100- 25= 75".

3. The Attempt at a Solution
How could I do this problem using only algebra, rather than what I did with trial and error?
 
  • #13
Thank you everyone, I have understood
 

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