Different forms of linear equations

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The discussion centers on the equivalence of two forms of linear equations: ax + by = c and y = mx + c. It is argued that while both equations represent a line, the constants (c) in each form cannot be the same due to the manipulation of terms. Specifically, when rearranging the first equation, it becomes clear that the slope (m) and the constant (d) differ from those in the second equation. The conclusion drawn is that the coefficients must be numerically different for the equations to hold true. This clarification highlights a common misconception about the relationship between the two forms of linear equations.
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A while back in maths we were introduced to the linear equation in two forms:

a x + b y = c (1)

y = m x + c (2)

Now I can use both forms of these, but I was told that:

y = m x + c \Leftrightarrow a x + b y = c

where m = \frac{a}{b}

Thiis can't be right can it? As:

a x + b y = c

b y = c - a x

y = \frac{c}{b} - \frac{a x }{b}
 
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Obviously the c's in equations 1 and 2 are not the same. They cannot be as you have demonstrated.

Using y = \frac{c}{b} - \frac{a x }{b}

and y = m x + d,

then m = -\frac{a}{b} and

d = \frac{c}{b}
 
Astronuc said:
Obviously the c's in equations 1 and 2 are not the same. They cannot be as you have demonstrated.

Thanks. My teacher was saying the two forms are the same (ie: at least "c" in both equations are the same). I couldn't prove it, and nor could she, and we both forgot about it.
 
Both equations represent a line, but the coefficients must be numerically different.

Basically, one is dividing all terms in (1) by the coefficient (b) of y, and to be equal, the m = - (a/b) and c in equation 2 must be c/a, so the c's must be different.
 

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