stripedcat
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[math]dy/dx = x^2+x^2y, y(1)=2[/math]
I'm not sure what to do with the y(1)=2, presumably I want to do the equation and then find y and c?
[math]dy/dx=x^2(y+1)[/math]
[math]dy/y+1=x^2 dx[/math]
[math] ln(y+1)=x^3/3+C[/math]
[math]y=e^{x^3/3} - 1 + C[/math]
I'm assuming I did this part right?
I just plug in 2 where the y is and I where the x is, then solve for y and c? Is that how it works?
I'm not sure what to do with the y(1)=2, presumably I want to do the equation and then find y and c?
[math]dy/dx=x^2(y+1)[/math]
[math]dy/y+1=x^2 dx[/math]
[math] ln(y+1)=x^3/3+C[/math]
[math]y=e^{x^3/3} - 1 + C[/math]
I'm assuming I did this part right?
I just plug in 2 where the y is and I where the x is, then solve for y and c? Is that how it works?