MHB Differential Equation: Tangents & Normals to y=x^2

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To find the differential equation for the family of tangents to the curve y=x^2, one must use the derivative, which is y'=2a, to establish the equation of the tangent line at any point a. The equation of the tangent line can be expressed as y - y(a) = 2a(x - a). For the normals, which are perpendicular to the tangents, the slope is -1/(2a), leading to the normal line equation y - y(a) = -1/(2a)(x - a). Both the tangents and normals can be represented by their respective differential equations derived from these relationships. Understanding these concepts is crucial for solving problems related to tangents and normals in calculus.
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Problem:Find the differential equation satisfied (i) by the equation of the family of tangents to y=x^2 and (ii) by the equation of the family of normals to y=x^2.
 
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I presume you know that a tangent line to a graph has slope equal to the derivative of the function at the point of tangency. Surely you know that the derivative of y= x^2, at x= a, is y'= 2a. So what is the equation of the tangent line there? What differential equation does every such tangent line satisfy?

Do you know that a line "normal" to a graph is perpendicular to the tangent line at that point? And that the slope of a line, perpendicular to a line with slope "m", is -1/m?
 

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