dy/dt = 2 - 2ty(adsbygoogle = window.adsbygoogle || []).push({});

y(0) = 1

I am not asked to solve this (I know it's not easy to solve), but what I am asked is,

"for large values of t is the solution y(t) greater than, less than, or equal to 1/t"?

I would think less than because 1/e^(t^2) converges faster than 1/t, but at the same time I solved dy/dt = 0 and got y = 1/t, so I'm not sure what that signifies.

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# Differential Equations behavior for large t?

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