Differential Equations: Finding the General Solution

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The discussion focuses on solving the differential equation dy/dt = 1/(ty+t+y+1). The initial approach involved cross-multiplying and attempting to separate variables, leading to an incorrect integration. The correct factorization of the equation is identified as (t + 1)(y + 1), allowing for the separation of variables to yield (y + 1) dy = dt/(t + 1). After integrating both sides, the solution is derived as y = ±(sqrt(4ln|t+1| + 1) + 1)/2, with a note that constants do not need to be on both sides of the equation. The final advice emphasizes verifying the solution by differentiation to ensure it satisfies the original equation.
amsscorpio
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Hello, this is the first time I post here, I'm really stumped and tried everything, even my TI-89 calculator won't give me something nice XD

Homework Statement



Find the general solution of

dy/dt= 1/(ty+t+y+1)


Homework Equations


No relevant equations.


The Attempt at a Solution



The first step I did was,

(ty+t+y+1)dy = 1dt

by cross multiplying proportions.
I can't figure out anyway to separate my terms to the proper places...I then tried this:

integral( ty+t+y+1 dy ) = integral( 1dt )
and resulted in:

ty^2/2 + ty + y^/2 + y + c = t

But this leads me nowhere...Any ideas? Or should I come into conclusion that this differential equation is not valid and unable to do?
 
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Ahh I THOUGHT I tried everything XD simple algebra error...

I found that (ty + t + y + 1) = (t + 1)(y + 1).

when factored...
then my next step would be

(y + 1) dy = dt/(t + 1).
which then i can integrate both sides to give me

y^2/2 + y + c = ln|t+1| + c

solving for y ultimately gives me

y = + or - (sqrt( 4ln|t+1| +1 ) +1 )/2

All over 2.

Am I right?
 
amsscorpio said:
Ahh I THOUGHT I tried everything XD simple algebra error...

I found that (ty + t + y + 1) = (t + 1)(y + 1).

when factored...
then my next step would be

(y + 1) dy = dt/(t + 1).
which then i can integrate both sides to give me

y^2/2 + y + c = ln|t+1| + c

solving for y ultimately gives me

y = + or - (sqrt( 4ln|t+1| +1 ) +1 )/2

All over 2.

Am I right?

I replied in your other thread that same hint but it looks correct.

But just know that when you have things like y2+y3=ln(x2+x+1)+e87x+x3+C

you don't always need to make 'y' the subject of the formula, you can leave it as is.
 
amsscorpio said:
Ahh I THOUGHT I tried everything XD simple algebra error...

I found that (ty + t + y + 1) = (t + 1)(y + 1).

when factored...
then my next step would be

(y + 1) dy = dt/(t + 1).
which then i can integrate both sides to give me

y^2/2 + y + c = ln|t+1| + c
You don't need constants on both sides in the equation above.
amsscorpio said:
solving for y ultimately gives me

y = + or - (sqrt( 4ln|t+1| +1 ) +1 )/2
Now you don't have any constants. The constant that should have been on the right side in your previous equation will show up in this one inside the radical.
amsscorpio said:
All over 2.

Am I right?
You can check by differenting and seeing whether it is a solution of the original differential equation. You might want to make life a bit easier on yourself by working with y2 rather than y, differentiating implicitly.
 
Ahh I don't know how to choose best answer + feedback on yahoo answers lol, I did it to have more chances of geting help, thank you and yes I will remember that.
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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