Differentiating delta function composed with a function

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The discussion centers on evaluating the integral of the second derivative of a delta function, specifically the expression ∫ δ(f(x))'' g(x) dx. Participants clarify the need for context regarding the derivative of the delta function and suggest using integration by parts as a potential method. Key identities related to the delta function's derivatives and their integration properties are shared, emphasizing the relationship between the delta function and its argument's derivatives. The discussion highlights the importance of understanding the behavior of delta functions in the context of integration. Overall, the conversation seeks to establish a clearer approach to solving the integral involving the delta function's derivatives.
rms502
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Dear all,
I just wondered whether there was any standard identity to help me solve this equation:
$$ \int \delta(f(x))^{\prime\prime}g(x) dx $$
Thanks in advance for your help.
 
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You don't have an equation.

I am not sure what you mean by the derivative of the delta function (derivative with respect to what?).

Integration by parts twice might be an approach.
 
Several things to consider
$$
\delta(\mathop{f}(x))''=\mathop{f}''(x) \delta (x)+(\mathop{f}'(x))^2 \delta '' (x) \\
\int \! \delta ^{(n)} (x) \, \mathop{f} (x) \, \mathop{dx}=(-1)^n\int \! \delta (x) \, \mathop{f ^{(n)}} (x) \, \mathop{dx}\\
\int \! \delta (\mathop{f} (x)) \, \, \mathop{g} (x) \mathop{dx}=\sum_{x \in f^{-1}(0)} \mathop{g}(x)
$$
 
We all know the definition of n-dimensional topological manifold uses open sets and homeomorphisms onto the image as open set in ##\mathbb R^n##. It should be possible to reformulate the definition of n-dimensional topological manifold using closed sets on the manifold's topology and on ##\mathbb R^n## ? I'm positive for this. Perhaps the definition of smooth manifold would be problematic, though.

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