Differentiating delta function composed with a function

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SUMMARY

The discussion focuses on the integration of the second derivative of the delta function, specifically the equation $$ \int \delta(f(x))^{\prime\prime}g(x) dx $$. Key insights include the application of integration by parts and the identities involving the delta function, such as $$ \delta(f(x))'' = f''(x) \delta(x) + (f'(x))^2 \delta''(x) $$ and $$ \int \delta^{(n)}(x) f(x) dx = (-1)^n \int \delta(x) f^{(n)}(x) dx $$. These identities are crucial for solving the integral involving the delta function and a function g(x).

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rms502
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Dear all,
I just wondered whether there was any standard identity to help me solve this equation:
$$ \int \delta(f(x))^{\prime\prime}g(x) dx $$
Thanks in advance for your help.
 
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You don't have an equation.

I am not sure what you mean by the derivative of the delta function (derivative with respect to what?).

Integration by parts twice might be an approach.
 
Several things to consider
$$
\delta(\mathop{f}(x))''=\mathop{f}''(x) \delta (x)+(\mathop{f}'(x))^2 \delta '' (x) \\
\int \! \delta ^{(n)} (x) \, \mathop{f} (x) \, \mathop{dx}=(-1)^n\int \! \delta (x) \, \mathop{f ^{(n)}} (x) \, \mathop{dx}\\
\int \! \delta (\mathop{f} (x)) \, \, \mathop{g} (x) \mathop{dx}=\sum_{x \in f^{-1}(0)} \mathop{g}(x)
$$
 

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