Diffraction limite of the human eye

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SUMMARY

The diffraction limit of the human eye, when considering a pupil diameter of 0.8 centimeters and a visible light wavelength of 500 nanometers, is calculated to be approximately 2.5 x 10^5. This value is derived using the formula for diffraction limit, which involves multiplying the wavelength of light by the inverse of the diameter of the aperture. Consequently, the resulting angular resolution is about 16 arcseconds. This calculation is crucial for understanding the optical limitations of human vision.

PREREQUISITES
  • Understanding of optical physics principles
  • Familiarity with diffraction and its effects on imaging
  • Knowledge of basic trigonometry for angular measurements
  • Experience with light properties, specifically wavelength
NEXT STEPS
  • Research the Rayleigh criterion for diffraction-limited systems
  • Explore the impact of pupil size on visual acuity
  • Learn about optical instruments and their diffraction limits
  • Investigate the relationship between wavelength and resolution in imaging systems
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Optical physicists, vision scientists, and anyone interested in the limitations of human vision and optical systems.

oldspice1212
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Calculate the diffraction limit of the human eye, assuming a wide-open pupil so that your eye acts like a lens with diameter 0.8 centimeter, for visible light of 500-nanometer wavelength.

Is there a formula for this? There are two other parts to this question, but if I get this the others won't be hard to get.
 
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Nvm I got it diffraction limit ~ 2.5 * 10^5 therefore you multiply it by wavelength of light/ diameter of telescope getting 16 ".
 

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