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Homework Help: Dilution Chemistry Problems i dont get it >.<

  1. Nov 30, 2007 #1
    ok, our teacher showed us a ton of stuff today, includeing molarity and dilution. i understand molarity but not dilution...any help please?

    1. The problem statement, all variables and given/known data
    the problems are all like this:
    *0.005 L of 1.0 M Hcl is diluted w/ water to 0.125 L
    *100.0 ML of 2.0 M HCL is diluted with water to 200 mL.

    3. The attempt at a solution
    now, the formula given is M1V1=M2V2

    so i would:
    for some reason that looks wrong, but like i said, i just dont get it...the teach was a sub, and made it all confusing-like <.<

    any help would be appreciated...
  2. jcsd
  3. Nov 30, 2007 #2
    well you interpreted all the variables incorrectly


    [tex]M_{2}=\mbox{Molarity}_{\mbox{final after dilution}}[/tex]


    [tex]V_{2}=\mbox{Volume}_{\mbox{final after dilution}}[/tex]

    so to answer your first question

    [tex]M_{1}=\mbox{1.0 M HCL}[/tex]


    and so, all you need to do is solve for final Volume

    [tex]M_{1} \times V_{1} = M_{2} \times V_{2}[/tex]

    *also, always pay attention to your final units
    Last edited: Nov 30, 2007
  4. Nov 30, 2007 #3
    It looks to me like your trying to use Boyles Law P1V1=P2V2, I dont think that applies to your problem. Other thing I noticed is the you converted 100ML to 10L, it should be .1L

    Also it seems as though part of the question is missing.
  5. Nov 30, 2007 #4
    Boyle's Law has nothing to do with this problem. He is simply looking for the final Molarity after dilution.
    Last edited: Nov 30, 2007
  6. Nov 30, 2007 #5
    Ok, My bad.
  7. Nov 30, 2007 #6
    Is ok, I'm in Organic 1 and I'm currently reading General Chemistry by Linus Pauling :-] There is still a lot to learn.
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