Dimension formulas for Lie algebras

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SUMMARY

The dimension formulas for classical Lie algebras are clearly defined. For SO(2n) or D_n, the dimension is calculated using the formula SO(N) = (N*(N-1))/2, exemplified by SO(8) yielding a dimension of 28. The discussion also seeks dimension formulas for SU(N+1) (A_n), SO(2n+1) (B_N), and Sp(n) (C_n). Additionally, it is established that the total number of roots equals the dimension minus the rank, with the number of positive roots being half of this quantity.

PREREQUISITES
  • Understanding of classical Lie algebras
  • Familiarity with dimension and rank concepts in algebra
  • Knowledge of root systems in Lie theory
  • Access to "Introduction to Lie Algebras and Representation Theory" by Humphreys
NEXT STEPS
  • Research the dimension formula for SU(N+1) (A_n)
  • Investigate the dimension formula for SO(2n+1) (B_N)
  • Explore the dimension formula for Sp(n) (C_n)
  • Study root systems and their applications in Lie algebra theory
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Mathematicians, theoretical physicists, and students specializing in algebra, particularly those focusing on Lie algebras and their applications in representation theory.

eherrtelle59
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Hi.

1. Can anyone definitively tell me what the dimension formula for the classical Lie algebras?

For example, I know for SO(2n) or D_n, the dimension formula is

SO(N)--> (N*(N-1))/2

E.g. SO(8) is 8*7/2 = 28.

Ok, so what about SU(N+1) i.e. A_n, SO(2n+1) i.e. B_N and Sp(n) i.e. C_n ?

2. I have (using # of simple roots = the rank )

that # total roots = dim (above) - rank

and therefore the # of positive roots is half of this quantity (i.e. (dim-rank)/2 )

Any help would be great. Thanks!
 
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eherrtelle59 said:
Hi.

1. Can anyone definitively tell me what the dimension formula for the classical Lie algebras?

For example, I know for SO(2n) or D_n, the dimension formula is

SO(N)--> (N*(N-1))/2

E.g. SO(8) is 8*7/2 = 28.

Ok, so what about SU(N+1) i.e. A_n, SO(2n+1) i.e. B_N and Sp(n) i.e. C_n ?

2. I have (using # of simple roots = the rank )

that # total roots = dim (above) - rank

and therefore the # of positive roots is half of this quantity (i.e. (dim-rank)/2 )

Any help would be great. Thanks!



I'm not sure, but I'd say most decent books in Lie Algebras mention this. Anyway, Humphreys's "Int. to Lie Algebras and Repres. Theory" does.

DonAntonio
 

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