Dimension of 7x7 Matrices w/ Zero Trace: 48

  • Context: Undergrad 
  • Thread starter Thread starter TMac92
  • Start date Start date
  • Tags Tags
    Dimension
Click For Summary
SUMMARY

The dimension of the set of 7x7 matrices with zero trace is definitively 48. This conclusion arises from the general formula for the dimension of an n x n matrix, which is n^2. For a 7x7 matrix, this results in a dimension of 49. However, since one diagonal element must be determined to ensure the trace equals zero, the dimension reduces by one, leading to a final dimension of 48. This calculation is supported by the relationship between the kernel and image dimensions in linear mappings.

PREREQUISITES
  • Understanding of matrix dimensions and linear algebra concepts
  • Familiarity with the concept of matrix trace
  • Knowledge of kernel and image in linear transformations
  • Basic proficiency in mathematical notation and equations
NEXT STEPS
  • Study the properties of matrix trace and its implications in linear algebra
  • Explore the relationship between kernel and image in linear mappings
  • Learn about the implications of zero trace in various applications of matrices
  • Investigate higher-dimensional matrices and their properties
USEFUL FOR

Students and professionals in mathematics, particularly those focusing on linear algebra, matrix theory, and applications in fields such as physics and engineering.

TMac92
Messages
2
Reaction score
0
1. Homework Statement


Find the dimension of the set of 7x7 matrices with zero trace

Relevant Equations
The dimension of a standard basis matrix n x n is n^2
Zero trace = sum of diagonal elements = 0

Attempt at Solution
I started with dim(M) = n^2 where M is an nxn matrix.
Then I assume you would have to subtract the dimension of an nxn matrix with zero trace
dim(M with zero trace) = 1

So in this case where M is 7x7
The dimension of the set of all 7x7 matrices with zero trace would be 49-1 = 48?
 
Physics news on Phys.org
you are free to fill all the entries of your matrix except for one of the diagonal elements (say x1, 1). Any choice of the other 6 diagonal elements will fix x1, 1 as the trace has to be 0. So yes you are right the dimension is 72 - 1 = 48.

easier: dim kernel + dim image = dim space

A trace is a real number so dim image = 1 so dim kernel = n2 - 1
 
Last edited:
its the kernel of a map to the scalars. check whether that map is linear and you are on your way.
 

Similar threads

  • · Replies 2 ·
Replies
2
Views
3K
  • · Replies 4 ·
Replies
4
Views
3K
Replies
15
Views
2K
Replies
5
Views
5K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 3 ·
Replies
3
Views
4K
  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 25 ·
Replies
25
Views
4K
  • · Replies 12 ·
Replies
12
Views
2K
  • · Replies 1 ·
Replies
1
Views
1K