Dimensionless physical quantities

Click For Summary
A dimensionless physical quantity has no associated units, and the discussion revolves around determining whether the constant alpha, defined as e²/ħc4(π)ε₀, is dimensionless. The Greek letters in the equation represent physical constants, which can be researched to understand their dimensions. If the units of these constants cancel out, then alpha is indeed dimensionless. An example provided is the angle measured in radians, which is a ratio of lengths that results in a unitless quantity despite being assigned a unit for clarity. Understanding these concepts clarifies the nature of dimensionless quantities in physics.
J-Girl
Messages
38
Reaction score
0
Hi:) A question that I don't understand, and my feeble attempt to answer it. Can anybody give any heads up on this one?
If a physical quantity is dimensionless, it has no units attatched to it. Determine if the following constant is dimensionless and show your reasoning"

\alpha= e^2/\hbarc4(Pi)\epsilon_{}_{0}
do all these greek scripted letters just stand for constants, and is it dimensionless because there are no S.I units in the equation? I am assuming constants like 4 and Pi are not units.
im so confused!:(
 
Physics news on Phys.org
4 and pi are just numbers, they do not have any physical dimensions.

Yes, the Greek letters are physical constants. You can look them up in order to figure out what their dimensions are. Then you can figure out the dimensions of alpha. If that product of constants is such that all of the units of the individual factors cancel each other out, then alpha is dimensionless.

As an example of dimensionless quantity (albeit one we still assign "units" to): an angle in the radian system is defined as the ratio of two lengths (arc length over radius). As a result, the angle has units of m/m, which cancels out, and the result is unitless (just a number). However, in order to make it clear that this number refers to an angle, we assign it units in "radians", but these are not really units in the traditional sense, since they are measuring a dimensionless quanity, whereas a unit like the metre is used to measure a quantity that has the dimension of length, and a unit like the second is used to measure a quantity that has the dimension of time.
 
thanks for ur help:)
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

Similar threads

  • · Replies 29 ·
Replies
29
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
Replies
2
Views
1K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
Replies
12
Views
2K
Replies
1
Views
6K
Replies
6
Views
3K
  • · Replies 18 ·
Replies
18
Views
9K
  • · Replies 37 ·
2
Replies
37
Views
5K