Dimensions and Dimensional analysis question

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In the kinetic energy formula E = 1/2 mv², the numerical factor 1/2 is dimensionless and does not influence the dimensional analysis, which focuses on basic dimensions like length, mass, and time. Dimensional analysis can show relationships between formulas but cannot calculate numerical factors, requiring more advanced methods for such evaluations. The dimensional formula for energy is E = ML²T⁻², which does not differentiate between kinetic and potential energy. Additionally, dimensional analysis treats energy density and pressure similarly, despite their different physical meanings. Thus, while dimensional analysis is useful, it has limitations in establishing strict equivalence between different formulas.
Zerocool97
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In this formula, E = 1/2 mv²

1/2 is not considered as it does not have any dimension. But then does it not affect the formula. Why? Explain! Please
 
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Welcome to PF;
Of course the value of 1/2 affects the formula... what is there to explain?
 
That's a limitation of dimensional analysis. numerical factors such as 1/2 in the formula for the kinetic energy cannot be calculated by dimensional analysis. Some more advanced calculation method must be used.
 
Zerocool97 said:
In this formula, E = 1/2 mv²

1/2 is not considered as it does not have any dimension. But then does it not affect the formula. Why? Explain! Please

Dimensional analysis is generally done with a few chosen "basic" dimensions. For most problems in Newtonian mechanics, length, mass and time (LMT) are sufficient. For energy, dimensions are: E=ML^{2}T^{-2}. The dimensional formula does not distinguish between kinetic and potential energy. Dimensionless values such as 1/2 in the KE formula do not appear in the dimensional formula.

Also, dimensional formulas do not distinguish between energy density and pressure. Both are represented by the formula ML^{-1}T^{-2}. The difference is that energy density is a scalar quantity and pressure is a vector quantity.

DA is useful in showing relationships between different formulas used in physics. That doesn't mean that different formulas with the same dimensional formula are necessarily strictly equivalent. They may only be dimensionally equivalent.
 
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I do not have a good working knowledge of physics yet. I tried to piece this together but after researching this, I couldn’t figure out the correct laws of physics to combine to develop a formula to answer this question. Ex. 1 - A moving object impacts a static object at a constant velocity. Ex. 2 - A moving object impacts a static object at the same velocity but is accelerating at the moment of impact. Assuming the mass of the objects is the same and the velocity at the moment of impact...

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