Direct sum decomposition into orthogonal subspaces

  • Context: High School 
  • Thread starter Thread starter sindhuja
  • Start date Start date
Click For Summary
SUMMARY

The discussion focuses on the concept of direct sum decomposition into orthogonal subspaces in the context of quantum information processing, specifically for an n-qubit system represented by a vector space V of dimension N = 2^n. It explains that any measurement device associated with this system can be described by a self-adjoint operator, whose eigenvalues correspond to possible measurement outcomes. The vector space V can be decomposed into orthogonal subspaces S1, S2, ..., Sk, where each subspace corresponds to the eigenspaces of the operator. This decomposition is crucial for understanding how measurements affect the state of quantum systems.

PREREQUISITES
  • Understanding of quantum mechanics principles, particularly n-qubit systems.
  • Familiarity with linear algebra concepts, including vector spaces and eigenvalues.
  • Knowledge of self-adjoint operators and their properties in quantum mechanics.
  • Basic grasp of Hilbert spaces and orthonormal bases.
NEXT STEPS
  • Study the properties of self-adjoint operators in quantum mechanics.
  • Learn about eigenvalues and eigenvectors in the context of quantum measurements.
  • Explore the concept of Hilbert spaces and their applications in quantum computing.
  • Investigate the implications of measurement in quantum systems, particularly regarding degenerate eigenvalues.
USEFUL FOR

Quantum physicists, quantum computing researchers, and students studying quantum information theory will benefit from this discussion, particularly those interested in the mathematical foundations of quantum measurements and state decomposition.

sindhuja
Messages
3
Reaction score
2
Hello All, I am trying to understand quantum information processing. I am reading the book "Quantum Computing A Gentle Introduction" by Eleanor Rieffel and Wolfgang Polak. I want to understand the following better:

" Let V be the N = 2^n dimensional vector space associated with an n-qubit system. Any device that measures this system has an associated direct sum decomposition into orthogonal subspaces V = S1 ⊕ · · · ⊕ Sk for some k ≤ N. The number k corresponds to the maximum number of possible measurement outcomesfor a state measured with that particular device."

Could anyone explain the intuition behind this statement. I think it is a quiet simple beginner level concept which I have not been getting a satisfactory explanation for. Thank you!
 
Physics news on Phys.org
I don't know this book, but I guess what's meant is the following: If you measure some observable (in this case on a system ##n## qubits), this observable is described by some self-adjoint operator on the ##2^n##-dimensional Hilbert space, describing the ##n##-qubit system. You can think of it as a matrix ##\hat{A}## operating on ##\mathbb{C}^{2^n}##-column vectors, which are the components of a vector wrt. an aribtrary orthonormal basis (e.g., the product basis of the ##n## qubits). The possible outcomes of measurements are the eigenvalues of this operator/matrix. To each eigenvalue ##a## there is at least one eigenvector. There's always a basis of eigenvectors, and you can always choose this basis to be an orthonormal set. The eigenvectors for each eigenvalue ##a## span a subspace ##S_i=\mathrm{Eig}(a_i)##. The vectors in eigenspaces of different eigenvalues are always orthogonal to each other (again, because the matrix is self-adjoint). Thus the entire vector space is decomposed into the orthogonal sum of these eigenspaces, ##V=S_1 \oplus S_2 \oplus \cdots \oplus S_k##, where the ##a_i## with ##i \in \{1,\ldots,k \}## are the different eigenvectors. Of course the dimensions of these subspaces are such that
$$\sum_{i=1}^k \mathrm{dim} \text{Eig}(a_i)=\mathrm{dim} V=2^n.$$
 
  • Like
Likes   Reactions: Haborix
You can also think of it as saying that when there are degenerate eigenvalues, a measuring device capable of measuring only the associated observable cannot give complete state information. The measuring device is incapable of resolving the decomposition of the state within the degenerate subspace, ##S_i##.
 
  • Like
Likes   Reactions: vanhees71

Similar threads

  • · Replies 8 ·
Replies
8
Views
3K
  • · Replies 62 ·
3
Replies
62
Views
10K
  • · Replies 8 ·
Replies
8
Views
3K
Replies
5
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 11 ·
Replies
11
Views
3K
  • · Replies 35 ·
2
Replies
35
Views
6K
  • · Replies 87 ·
3
Replies
87
Views
8K
Replies
4
Views
2K